mysql - select query in where condition 基于主要的select query values

Question

我有三个这样的表: 发票表

╔════╦════════════╦
║ id ║ invoice_id ║
╠════╬════════════╬
║  1 ║     1      ║
║  2 ║     2      ║
║  3 ║     3      ║
╚════╩════════════╩ 

账单表

╔════╦════════════╦══════════╗
║ id ║ invoice_id ║bill_amt  ║
╠════╬════════════╬══════════╣
║  1 ║     1      ║   50     ║
║  2 ║     1      ║   80     ║  
║  3 ║     2      ║   25     ║
║  4 ║     2      ║   55     ║
║  5 ║     3      ║   60     ║
║  6 ║     3      ║   55     ║
╚════╩════════════╩══════════╝

信用表

╔════╦════════════╦══════════╗
║ id ║ invoice_id ║credit_amt║
╠════╬════════════╬══════════╣
║  1 ║     1      ║   50     ║
║  3 ║     2      ║   25     ║
║  4 ║     2      ║   55     ║
║  5 ║     3      ║   60     ║
╚════╩════════════╩══════════╝

我需要所有 invoice_id，其中 (sum(那个 invoice_id 的 credit_amt)-sum(那个 invoice_id 的 bill_amt)) > 0 到目前为止我试过了

select invoice_id from invoice_table where 
((select sum(bill_amt) FROM bill_table) - (select sum(credit_amt) FROM credit_table)) > 0

换句话说，我想要这个结果:

╔════════════╗
║ invoice_id ║
╠════════════╣
║     1      ║
║     3      ║
╚════════════╝

Answer 1

试试这个:

SELECT i.invoice_id
FROM invoice_table i 
    LEFT JOIN
    (SELECT invoice_id, SUM(bill_amt) AS sum_bill_amt 
     FROM bill_table
     GROUP BY invoice_id) b 
    ON i.invoice_id = b.invoice_id
    LEFT JOIN 
    (SELECT invoice_id, SUM(credit_amt) AS sum_credit_amt 
     FROM credit_table
     GROUP BY invoice_id) c 
    ON i.invoice_id = c.invoice_id
WHERE b.sum_bill_amt - c.sum_credit_amt > 0;