我有一个简单的功能可以从我的数据库中删除帐户。我是这样写的
public function removeAccount($email) {
$response = array('code' => 0, 'error' => false);
$stmt = $this->conn->prepare("SELECT id FROM user WHERE email = ?");
$stmt->bind_param("s", $email);
$stmt->execute();
$result = $stmt->get_result();
if ($result->num_rows) {
$user = $result->fetch_assoc();
$id = $user['id'];
$stmt->close();
$stmt = $this->conn->prepare("DELETE FROM number_list WHERE user_id = ?");
$stmt->bind_param("i", $id);
$stmt->execute();
$stmt->close();
$stmt = $this->conn->prepare("DELETE FROM number_status WHERE user_id = ?");
$stmt->bind_param("i", $id);
$stmt->execute();
$stmt->close();
$stmt = $this->conn->prepare("INSERT INTO old_user(email,serial,premium) SELECT email, device_id, membership FROM user WHERE id = ?");
$stmt->bind_param("i", $id);
$stmt->execute();
$stmt->close();
$stmt = $this->conn->prepare("DELETE FROM user WHERE id = ?");
$stmt->bind_param("i", $id);
$stmt->execute();
$stmt->close();
if ($stmt->affected_rows) {
$response["code"] = 1;
}
}
return $response;
}
它在下面的行中给我警告
if ($stmt->affected_rows) {
我已经搜索了解决它的方法,但不知道哪里出了问题以及可以解决它的方法。请检查并让我知道是否有人对此有想法。非常感谢。
最佳答案
$stmt = $this->conn->prepare("DELETE FROM user WHERE id = ?");
$stmt->bind_param("i", $id);
$stmt->execute();
if($stmt->affected_rows > 0) { $response["code"] = 1; }
$stmt->close();
在这种情况下,我们检查是否有任何行得到更新。作为引用,这里是 mysqli::$affected_rows
返回值的用法。
-1 - 查询返回错误;如果 execute()
0 - UPDATE
上没有更新记录,没有行与 WHERE
子句匹配,或者没有执行查询
大于 0 - 返回受影响的行数;相当于 mysqli_result::$num_rows
for SELECT
关于php - 尚不允许属性(property)访问,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/51550819/