给定以下字符串:
var snippet = "1111 West Main Street Beverly Hills, CA 90210 Phone: 123.456.7891"
如何提取“电话:”之后的所有内容
所以在这种情况下我想要
phone = 123.456.7891
我已经试过了:
if let range = snippet.rangeOfString("Phone:") {
let phone = snippet.substringToIndex(range.startIndex)
print(phone) // prints 1111 West Main Street Beverly Hills, CA 90210
}
但这会打印之前的所有内容,我需要之后的所有内容。
最佳答案
在 Swift 4 中,使用 upperBound
和下标运算符以及开放范围:
let snippet = "1111 West Main Street Beverly Hills, CA 90210 Phone: 123.456.7891"
if let range = snippet.range(of: "Phone: ") {
let phone = snippet[range.upperBound...]
print(phone) // prints "123.456.7891"
}
或者考虑修剪空白:
if let range = snippet.range(of: "Phone:") {
let phone = snippet[range.upperBound...].trimmingCharacters(in: .whitespaces)
print(phone) // prints "123.456.7891"
}
顺便说一下,如果你想同时获取两者,正则表达式可以做到这一点:
let snippet = "1111 West Main Street Beverly Hills, CA 90210 Phone: 123.456.7891"
let regex = try! NSRegularExpression(pattern: #"^(.*?)\s*Phone:\s*(.*)$"#, options: .caseInsensitive)
if let match = regex.firstMatch(in: snippet, range: NSRange(snippet.startIndex..., in: snippet)) {
let address = snippet[Range(match.range(at: 1), in: snippet)!]
let phone = snippet[Range(match.range(at: 2), in: snippet)!]
}
有关 Swift 的早期版本,请参阅 previous revision of this answer。
关于Swift:如何在特定字符集之后获取所有内容,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/34073610/