php - 将 SQL 转换为 Laravel

Question

假设我有这个:

SELECT * FROM drivers where driver_number NOT IN (SELECT driver_number FROM buses) AND station_id = 2 OR driver_number = 'Dr_02'

并显示这些数据

然后我想以 laravel 查询的形式获取这些数据，这就是我所做的:

$drivers = Driver::whereRaw('driver_number not in (select driver_number from buses) AND station_id = ? ', [$station_id].' OR id = ?', [$bus->Driver_id])
                    ->get();

但是我得到这个错误:

SQLSTATE[42000]: Syntax error or access violation: 1064 You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near 'driver_number not in (select driver_number from buses) AND station_id = ?' at line 1 (SQL: select * from drivers where id = 2 driver_number not in (select driver_number from buses) AND station_id = ?)

我认为它的表达方式有误，那就是类型系统错误。因此，如果有人知道更好的方法，您可以提供帮助。

Answer 1

这在 Laravel 中很难处理。 WHERE 子句中的逻辑基本上是 (A 和 B)或 C，其中条件 A 可以用 NOT EXISTS 表示 MySQL 中的子查询。

$drivers = DB::table('Driver d')
    ->where(function($query1) {
        return $query1
            ->whereNotExists(function ($query2) {
                $query2->select(DB::raw(1))
                    ->from('buses b')
                    ->whereRaw('d.driver_number = b.driver_number');
              })
            ->where('station_id', '=', '2');
    })
    ->orWhere('driver_number', '=', 'Dr_02');
->get();