php - 我想在where条件下访问null的记录

Question

在我的 crossing_cash_memo 表中 due_to 列中，值为 consignee,cash 其他为 Null.I想要隐藏 cash 数据并显示剩余数据，但未显示我的空数据。

我正在尝试这样:

  public function fetchDue($rec_type){
  $query = $this->db->select('user.user_full_name as consignor,user1.user_full_name as consignee,c.*')
         ->from('crossing_cash_memo c')

         ->join('ts_users user', 'c.consignor_name=user.user_id')
         ->join('ts_users user1', 'c.consignee_name=user1.user_id')

         ->where('c.memo_status','cash_memo')
         ->where_not_in('c.due_to','cash') 
         ->order_by('c.lr_no','asc')
         ->get();                            
         return $query->result();
  }

我如何在 where 条件下显示 NULL 记录

Answer 1

试试这个

    public function fetchDue($rec_type){
       $query = $this->db->select('user.user_full_name as consignor,user1.user_full_name as consignee,c.*')
     ->from('crossing_cash_memo c')

     ->join('ts_users user', 'c.consignor_name=user.user_id', 'left')
     ->join('ts_users user1', 'c.consignee_name=user1.user_id', 'left')

     ->where(array('c.memo_status' => 'cash_memo', 'c.due_to !=' =>'cash'))
     ->order_by('c.lr_no','asc')
     ->get();                            
     return $query->result();
  }