sql - 搜索结果按特定顺序显示？

Question

SELECT id FROM films WHERE id IN (90,4,40)

结果

4
40
90

但我希望它返回 90,4,40 我应该做什么？ (mysql)

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抱歉，还有一个问题:

SELECT id FROM films WHERE id IN (90,4,40) ORDER BY FIELD(id, 90, 4, 40) 可以 但说实话

 for ( $i = 1; $i <10; $id ++ ){
     $IDarray[] = random();
 }


SELECT id FROM films WHERE id IN "(". implode(',',$IDarray). " ) ";

我想按上面的 ID 排序，但 ID 是随机的，我想保持 ID 的随机顺序

Answer 1

ORDER BY CASE `id` WHEN 90 THEN 0
                   WHEN 4 THEN 1
                   WHEN 40 THEN 2
                   ELSE 3
         END CASE

或

ORDER BY FIND_IN_SET(`id`, '90,4,40')

或

ORDER BY FIELD(`id`, 90, 4, 40)