我想更新来自某个 ID 的表“tourneygamesISF”字段“op1score”和“op2score”中的表“tourneyteamsISF”字段“pointsfavor”和“pointscontra”。
例如:
Table name = tourneygamesISF
op1(name of row) vs. op2 - op1score = 25 - op2score = 20
我要更新这个:
op1: (from: tourneygamesISF) = ID in tourneyteamsISF
+ pointsfavor = 25 (to: tourneyteamsISF)
+ pointscontra = 20 (to: tourneyteamsISF)
op2: (from: tourneygamesISF) = ID in tourneyteamsISF
+ pointsfavor = 20 (to: tourneyteamsISF)
+ pointscontra = 25 (to: tourneyteamsISF)
到目前为止我有以下内容
UPDATE tourneyteamsISF
INNER JOIN tourneygamesISF g1 ON (tourneyteamsISF.ID = g1.op1)
INNER JOIN tourneygamesISF g2 ON (tourneyteamsISF.ID = g2.op2)
SET pointsfavor = pointsfavor
+ IF(g1.op1score > g1.op2score, g1.op1score - g1.op2score, 0)
+ IF(g2.op2score > g2.op1score, g2.op2score - g2.op1score, 0)
, pointscontra = pointscontra
+ IF(g1.op1score < g1.op2score, g1.op2score - g1.op1score, 0)
+ IF(g2.op2score < g2.op1score, g2.op1score - g2.op2score, 0)
WHERE ID = 1;
但它给出了错误:Column 'ID' in where clause is ambiguous
我的表格是这样的:
TABLE tourneyteamsISF
ID integer autoincrement primary key,
name varchar,
pointsfavor integer,
pointscontra integer
TABLE tourneygamesISF
ID integer autoincrement primary key,
op1 integer,
op2 integer,
op1score integer, /*score for team1*/
op2score integer /*score for team2*/
我知道它必须对表团队和游戏的 ID 进行命名,但我感到困惑和困惑。我将感谢我能得到的所有帮助。
最佳答案
WHERE ID = 1;
<- 这是您的问题。在它前面加上表名,它会编译没有任何问题。
例如。 WHERE g1.ID = 1;
发生此错误是因为 SQL 无法从您的 SELECT
语句中的表中识别您要使用的 ID
列。
关于php - 使用 INNER JOIN 更新表 - 帮助!,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/6507398/