mysql 查询但是两个不同的组依据

Question

如果我的数据是

Name - playerID - matchID - Innings - Runs
James   1   1   1   5
James   1   1   2   8
Darren  2   1   1   3
Darren  2   1   2   9
James   1   2   1   10
James   1   2   2   12
Darren  2   2   1   13
Darren  2   2   2   19

我的sql数据是

$query = "SELECT playerID, name,
        SUM(runs) AS runs_scored,
        MAX(runs) AS highest_score
    FROM matchPlayer GROUP BY playerID";

然后输出会是

James has scored 35 runs with a highest score of 18
Darren has scored 44 runs with a highest score of 19

现在我希望获得一场比赛中的最高总得分(即结合第 1 局和第 2 局)？ 我不知道如何开始这个查询:(

编辑 我需要的确切信息是最高匹配总数，因此 James 有 13 次来自 matchID 1 的组合运行和 22 次来自 matchID 2 的组合运行 - 所以我得到的答案是 22。

Answer 1

您需要分两个阶段进行:

SELECT ms.playerID, mp.name, SUM(ms.runs_by_match) AS runs_scored,
    MAX(ms.runs_by_match) as highest_score
FROM
    matchPlayer as mp
    INNER JOIN (
        SELECT playerID, matchID, SUM(runs) AS runs_by_match
        FROM matchPlayer
        GROUP BY playerID, matchID
    ) AS ms ON mp.playerID = ms.playerID
GROUP BY
    ms.playerID, mp.name