php - 使用此代码我只能得到一个结果

Question

<a href="add.php">add new product</a><br>
<br>

<?php

include("mysql.php");

$result = mysql_query("SELECT * FROM gallery ");

$just = mysql_fetch_array($result);
$num=mysql_num_rows($result);  

$table="";
$table.="<td>delete</td>";

$table.="<td>update</td>";
if ($num > 0 ) {
$i=0;

while($just = mysql_fetch_array($result))   
{
$num=mysql_num_rows($result);  
  {

$table .= "<tr>";

$table .= "<td><a href=\"delete.php?name=".$just['name']."&id=".$just['id']."\">".$just['title']."</a></td>";
$table .= "<td><a href=\"update.php?description=".$just['description']."&title=".$just['title']."&id=".$just['id']."\">".$just['title']."</a></td>";

  }
$table .= "</tr>";
while ($i < $num) {

$name = stripslashes(mysql_result($result,$i,"name"));
$title = stripslashes(mysql_result($result,$i,"title"));
$description = stripslashes(mysql_result($result,$i,"description"));

++$i; }
}
}


else { $table = '<tr><td colspan="2" align="center">Nothing found</td></tr>'; }

?>

<table border="1" cellpadding="1" cellspacing="2"><? echo $table ?></table>

早上好，在上面的代码中，我试图创建一个包含 2 列删除和更新的表，能够通过此页面管理 mysql，但是我只从 mysql 表中得到 1 行，尽管我期望有 4 行(保存了 4 行在 mysql 表中) 这里有什么问题，提前致谢

Answer 1

<a href="add.php">add new product</a><br>
<br>

<?php

include("mysql.php");

$result = mysql_query("SELECT * FROM `gallery`");

$num = mysql_num_rows($result);  

$table = "";
$table .= "<td>delete</td>";
$table.="<td>update</td>";

if ($num > 0 ) {
    $i=0;
    while($just = mysql_fetch_assoc($result)) {
        $num=mysql_num_rows($result);  
        $table .= "<tr>";
        $table .= "<td><a href=\"delete.php?name=".$just['name']."&id=".$just['id']."\">".$just['title']."</a></td>";
        $table .= "<td><a href=\"update.php?description=".$just['description']."&title=".$just['title']."&id=".$just['id']."\">".$just['title']."</a></td>";
    }
    $table .= "</tr>";
    while ($i < $num) {
        $name = stripslashes(mysql_result($result,$i,"name"));
        $title = stripslashes(mysql_result($result,$i,"title"));
        $description = stripslashes(mysql_result($result,$i,"description"));
        ++$i; 
    }
} else { 
    $table = '<tr><td colspan="2" align="center">Nothing found</td></tr>'; 
}
?>

<table border="1" cellpadding="1" cellspacing="2"><? echo $table ?></table>