在我的 MYSQL 数据库中,我有 2 个表:
+-------------------+ +---------------------------------+
| tags | | relationships |
+----+--------------+ +---------+---------+------+------+
| id | tag | | x_table | y_table | x_id | y_id |
+----+--------------+ +---------+---------+------+------+
| 1 | parent 1 | | tags | tags | 1 | 2 |
| 2 | child 1 | | tags | tags | 1 | 3 |
| 3 | child 2 | | tags | tags | 3 | 4 |
| 4 | grandchild 1 | +---------+---------+------+------+
+----+--------------+
我需要将这些关系加载到一个多维数组中。 child 的数量可以改变,深度也可以改变。每个关系树的深度也不同。
现在我读到递归函数比 PHP 等解释语言的循环慢,并且想知道是否有可能用循环来编写它,如果可以的话,它是否会比循环更快且占用资源更少使用递归函数?
多维数组的结构应该是这样的:
array(
'id' => $id_from_db,
'tag' => $tag_from_db,
'children' => array( /* Just like parent array or false/NULL */ )
)
编辑: SQLfiddle here
编辑:我创建了递归函数来实现这一点:
private function get_tags($id = false){
global $pdo;
$tags = array();
if(!$id)
$info = $pdo->query("SELECT DISTINCT
t.id,
t.tag
FROM tags t
JOIN relationships r
ON r.x_table = 'tags'
AND r.y_table = 'tags'
AND t.id NOT IN ( SELECT rb.y_id FROM relationships rb WHERE x_table = 'tags' AND y_table = 'tags' )
ORDER BY t.tag");
else
$info = $pdo->query("SELECT DISTINCT
t.id,
t.tag
FROM tags t
JOIN relationships r
ON r.x_table = 'tags'
AND r.y_table = 'tags'
AND r.x_id = " .(int)$id."
AND r.y_id = t.id
ORDER BY t.tag");
while($tag = $info->fetch(PDO::FETCH_ASSOC))
$tags[] = array('tag' => $tag['tag'], 'children' => $this->get_tags($tag['id']) );
if(!count($tags))
return false;
return $tags;
}
最佳答案
如果您不介意一次获取所有内容(2 个查询),您可以使用引用(标签的总数可能应该低于几百个,并且您可以将生成的构造缓存一段时间):
//fill tags
$tags[] = array()
foreach($pdo->query('SELECT * FROM tags')->fetchAll(PDO::FETCH_ASSOC) as $tag){
$tags[$tag['id']] = $tag;
}
//add relationships
$relation_query = $pdo->query("SELECT * FROM relationships
WHERE x_table='tags' AND y_table = 'tags'");
foreach($relation_query->fetchAll(PDO::FETCH_ASSOC) as $relationship){
//ensure targets exists:
if(!isset($tags[$relationship['x_id '])) $tags[$relationship['x_id '] = array();
if(!isset($tags[$relationship['y_id '])) $tags[$relationship['y_id '] = array();
if(!isset($tags[$relationship['x_id ']['children']))
$tags[$relationship['x_id ']['children'] = array();
//add as reference
$tags[$relationship['x_id ']['children'] = &$tags[$relationship['y_id '];
}
//pick the tag you want:
var_dump($tags[1]);
var_dump($tags[4]);
不是 closure
table , 或者只是 path enumeration (从幻灯片 18 开始,但整篇文章都值得一读)将为您提供更高的性能,以及仅查询子树的可能性。 Bill Karwin 的大力支持。
关于php - MYSQL - 多维数组 - 循环还是递归?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/16887634/