php - 从数据库中获取列名

Question

在这个程序中，我从数据库中获取了列名，但在尝试将其保存在数组中时，它会将最后一个列名存储在数组中。如何将 eash 列名存储在数组中？？？

$sql="SHOW COLUMNS from itasd2015sem1semester";
if(($result=$conn->query($sql))==true){
    while($row=$result->fetch_array()){
        for($i=0;$i<11;$i++){
            $sub[$i]=$row[0]."\n";
        }
    }
}

for($i=0;$i<sizeof($sub);$i++){
    echo $sub[$i];
}

它只打印最后一列的名称？？

$sql="SHOW COLUMNS from itasd2015sem1semester";
if(($result=$conn->query($sql))==true){
    while($row=$result->fetch_array()){
        for($i=0;$i<11;$i++){
            $sub[$i]=$row[$i]."\n";
        }
    }
}

for($i=0;$i<sizeof($sub);$i++){
    echo $sub[$i];
}

它显示一条通知..并且它还单独打印最后一列。

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Notice: Undefined offset: 8 in C:\xampp\htdocs\new\test1.php on line 21
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Notice: Undefined offset: 6 in C:\xampp\htdocs\new\test1.php on line 21
Notice: Undefined offset: 7 in C:\xampp\htdocs\new\test1.php on line 21
Notice: Undefined offset: 8 in C:\xampp\htdocs\new\test1.php on line 21
Notice: Undefined offset: 9 in C:\xampp\htdocs\new\test1.php on line 21
Notice: Undefined offset: 10 in C:\xampp\htdocs\new\test1.php on line 21
Notice: Undefined offset: 6 in C:\xampp\htdocs\new\test1.php on line 21
Notice: Undefined offset: 7 in C:\xampp\htdocs\new\test1.php on line 21
Notice: Undefined offset: 8 in C:\xampp\htdocs\new\test1.php on line 21
Notice: Undefined offset: 9 in C:\xampp\htdocs\new\test1.php on line 21
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Notice: Undefined offset: 9 in C:\xampp\htdocs\new\test1.php on line 21
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Notice: Undefined offset: 8 in C:\xampp\htdocs\new\test1.php on line 21
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Notice: Undefined offset: 9 in C:\xampp\htdocs\new\test1.php on line 21
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Notice: Undefined offset: 6 in C:\xampp\htdocs\new\test1.php on line 21
Notice: Undefined offset: 7 in C:\xampp\htdocs\new\test1.php on line 21
Notice: Undefined offset: 8 in C:\xampp\htdocs\new\test1.php on line 21
Notice: Undefined offset: 9 in C:\xampp\htdocs\new\test1.php on line 21
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Notice: Undefined offset: 8 in C:\xampp\htdocs\new\test1.php on line 21
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Notice: Undefined offset: 7 in C:\xampp\htdocs\new\test1.php on line 21
Notice: Undefined offset: 8 in C:\xampp\htdocs\new\test1.php on line 21
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Notice: Undefined offset: 10 in C:\xampp\htdocs\new\test1.php on line 21
Notice: Undefined offset: 6 in C:\xampp\htdocs\new\test1.php on line 21
Notice: Undefined offset: 7 in C:\xampp\htdocs\new\test1.php on line 21
Notice: Undefined offset: 8 in C:\xampp\htdocs\new\test1.php on line 21
Notice: Undefined offset: 9 in C:\xampp\htdocs\new\test1.php on line 21
Notice: Undefined offset: 10 in C:\xampp\htdocs\new\test1.php on line 21

Answer 1

试试这个:

$sql = "SHOW COLUMNS from itasd2015sem1semester";
if (($result = $conn->query($sql)) == true) {
    while ($row = $result->fetch_array()) {
        $sub[] = $row[0];
    }
}
for ($i = 0; $i < sizeof($sub); $i++) {
    echo $sub[$i];
}