php mysql嵌套查询 "where not in"

Question

我有两个表 test_category 和结果:

CREATE TABLE IF NOT EXISTS `test_category` (
  `_id` int(11) NOT NULL AUTO_INCREMENT,
  `score_type` varchar(50) NOT NULL,
  `sub_code` int(11) NOT NULL,
  `duration` varchar(10) NOT NULL,
  PRIMARY KEY (`_id`),
  KEY `sub_code` (`sub_code`)
)

CREATE TABLE IF NOT EXISTS `results` (
  `res_id` int(11) NOT NULL AUTO_INCREMENT,
  `user_id` int(11) NOT NULL,
  `score_type` int(11) NOT NULL,
  `score` int(11) NOT NULL,
  `date_taken` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP,
  PRIMARY KEY (`res_id`),
  KEY `user_id` (`user_id`),
  KEY `score_type` (`score_type`)
)

我想选择一些存在于 test_category 但不存在于结果中的列。

这是我试过但不起作用的 sql:

select _id, score_type from test_category where _id in ('13') and not in(select score_type from results where user_id=349);

Answer 1

您错过了在 AND 之后提及列名

试试这个，

SELECT _id, score_type FROM test_category WHERE _id IN
('13') AND _id NOT IN(SELECT score_type FROM results WHERE user_id=349);