mysql REGEXP匹配以2位数字结尾且仅以非数字开头的字符串

Question

我为此苦苦挣扎。

在 MySQL 中，我想在一列中查询以两位数结尾的字符串。我不在乎前面还有什么，只要最后一个字符是前面至少有一个非数字的两位数

例如，这些字符串应该匹配:

"Nov. 12th, 60"

"34 Bar 56"

"Foo-BAR-01"

"33-44-55"

"-------88"

"99"

当我这样做时:

SELECT <string> REGEXP <pattern>

现在，<pattern>位是我需要帮助的地方。

谢谢。

Answer 1

SELECT * FROM mytable WHERE mycolumn REGEXP "^.*[^0-9][0-9]{2}$";

正则解释:

^.*[^0-9][0-9]{2}$

Assert position at the beginning of the string «^»
Match any single character that is NOT a line break character «.*»
   Between zero and unlimited times, as few or as many times as needed to find the longest match in combination with the other quantifiers or alternatives «*»
Match any single character that is NOT present in the list below and that is NOT a line break character «[^0-9]»
   A character in the range between “0” and “9” «0-9»
Match a single character in the range between “0” and “9” «[0-9]{2}»
   Exactly 2 times «{2}»
Assert position at the very end of the string «$»