mysql - 在 SQL 中使用 Pivot 时的错误代码

Question

目前正在解决一个具有挑战性的问题，我一直在尝试解决我面临但无法解决的问题。非常感谢您的专业知识。

问题是:

旋转职业中的职业列，以便每个姓名按字母顺序排序并显示在其相应的职业下方。输出列标题应分别为 Doctor、Professor、Singer 和 Actor。

我的解决方案

SELECT
    [Doctor],
    [Professor],
    [Singer],
    [Actor]
FROM
    (SELECT 
         ROW_NUMBER() OVER (PARTITION BY Occupation ORDER BY Name) ma,
         [Name],
         [Occupations] 
     FROM 
         Occupation
    ) AS source 
PIVOT
    ( MAX([Name]) FOR [occupation] IN ([Doctor],[Professor],[Singer],[Actor]) ) as pv
ORDER BY ma

错误信息

ERROR 1064 (42000) at line 5: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '[Doctor],
    [Professor],
    [Singer],
    [Actor]
FROM
    (SELECT 
         ' at line 2

等待您的回复。谢谢

Answer 1

Mysql 不支持PIVOT操作符

使用条件聚合来转换数据。

由于名称分为 4 个不同的列，因此在旋转数据后按名称排序没有多大意义。

select 
Occupations,
max(case when occupation = 'Doctor' then name end) as Doctor,
max(case when occupation = 'Professor' then name end) as Professor,
max(case when occupation = 'Singer' then name end) as Singer,
max(case when occupation = 'Actor' then name end) as Actor
from Occupation
Group by Occupations

此外，您应该使用反引号 `` 而不是方括号 []