我想获得 StartDate 和 EndDate 之间的差值,但如果差值小于 0,我需要值 0(EndDate 可能在 StartDate 之前)。有没有办法在不重复 ROUND() 表达式的情况下在 SELECT 中执行此操作?
SELECT StartDate, EndDate,
IF(ROUND(TIMESTAMPDIFF(SECOND, StartDate, EndDate)/86400, 1) < 0, 0, ROUND(TIMESTAMPDIFF(SECOND, StartDate, EndDate)/86400, 1)) AS Duration
FROM table
WHERE StartDate <= '2016-06-02' AND EndDate >= '2016-06-01';
最佳答案
只需使用 GREATEST()
得到 0 和差值中的较大者。
SELECT StartDate, EndDate,
GREATEST(ROUND(TIMESTAMPDIFF(SECOND, StartDate, EndDate)/86400, 1), 0) AS Duration
FROM table
WHERE StartDate <= '2016-06-02' AND EndDate >= '2016-06-01';
关于MySQL 如果差异小于 0,则选择 0,否则选择差异,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/37056778/