php - Codeigniter MySQL 连接复杂

Question

我有几张表想用一个 id 一次性显示。

表A

编号 | isi a1 | isi a2

表B

编号 | id_a | isi b1 | isi b2

表C

编号 | id_a | isi c1 | isi c2

表D

编号 | id_a | isi d1 | isi d2

表E

编号 | id_a | isi e1 |伊西e2

我想显示 isi B1-E2，每个表在表 A 中都有 id_a = id。我不知道 mysql 连接，我试过这段代码

$this->db->select('BaseTbl.id, BaseTbl.tanggal, BaseTbl.atas_nama, BaseTbl.kerugian, BaseTbl.keterangan, BaseTbl.admin, BaseTbl.status');
$this->db->from('data_blacklist as BaseTbl');
$this->db->join('bl_rekening as Rekening, bl_telefon as Telefon, bl_bukti as Bukti, bl_pelapor as Pelapor', 'Rekening.id_blacklist = BaseTbl.id, Telefon.id_blacklist = BaseTbl.id, Bukti.id_blacklist = BaseTbl.id, Pelapor.id_blacklist = BaseTbl.id','left');

但它总是给我

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ' bl_telefon as Telefon, bl_bukti as Bukti, bl_pelapor as Pelapor ON `Rekening`.`' at line 3

我暂时不知道。任何想法？我使用 codeigniter

Answer 1

试试这个。您必须为每个表查询连接。你不能把它们结合起来

$this->db->select('BaseTbl.id, BaseTbl.tanggal, BaseTbl.atas_nama, BaseTbl.kerugian, BaseTbl.keterangan, BaseTbl.admin, BaseTbl.status');
$this->db->from('data_blacklist as BaseTbl',);
$this->db->join('bl_rekening as Rekening','Rekening.id_blacklist = BaseTbl.id','left');
$this->db->join('bl_telefon as Telefon','Telefon.id_blacklist = BaseTbl.id','left');
$this->db->join('bl_bukti as Bukti','Bukti.id_blacklist = BaseTbl.id','left');
$this->db->join('bl_pelapor as Pelapor','Pelapor.id_blacklist = BaseTbl.id','left');