php - 你如何 ORDER BY 两个表？

Question

我就是您所说的 MySQL 的“菜鸟”。我可以插入/编辑/选择东西，但比这更高级的东西让我很困惑。我的数据库中有两个表:

表“评论”

id      int(11)
review  varchar(2500)
game    int(11)
user    int(11)
title   varchar(200)`

和表“review_rating”

user    int(11)
review  int(11)     // Corresponds to `reviews.id`
like    tinyint(1)

这是我的问题:是否可以在 reviews 表上使用 ORDER BY 来按“like”= 1 的 review_ratings 总数对结果进行排序(其中 'review' = 'reviews' 表的 ID)除以 review_ratings 总数(其中 'review' = 'reviews' 表的 ID)。

示例:

SELECT * 
FROM `reviews` 
WHERE `game` = ? 
ORDER BY (total number of review_ratings where review = reviews.id and like = 1 / 
         total number of review_ratings where review = reviews.id) 
LIMIT 0, 10

Answer 1

SELECT  t.review,
        Score = CASE WHEN TotalReviews<> 0 THEN LikedReviews/TotalReviews ELSE NULL END
  FROM  (
              SELECT    *,
                    (SELECT COUNT(*) FROM review_rating WHERE review = r.review) AS TotalReviews ,
                    (SELECT COUNT(*) FROM review_rating WHERE review = r.review AND like = 1) AS LikedReviews,
              FROM  review r        
             WHERE  game = ?
         )t
ORDER BY t.review, Score