php - 如何在 PHP 中设计一个对象

Question

我可以从概念上理解这一点，但我无法确定正确的方法。

具体而言，需要执行以下操作的对象...

class Question {
  var $text;
  var $filters = array();
  var $banners = arrya(); //But this has to be within $filter somehow...
  ... //all getter and setter functions
}

现在我要查询数据库并返回一堆数据，比如 4 列。

QuestionText | Filter | Banner | Value

我想最终得到一个看起来像...的对象

Object
  Questions
   ->Question 1
     ->Text = Question One
     ->Filters
        ->Filter1
           ->Name = Ontario
           Banners
             Banner 1
              ->Name = Male
              ->Value = 20
             Banner 2
              ->Name = Famales
              ->Value = 20
        ->Filter2
           ->Name = Quebec
           Banners
           Banners
             Banner 1
              ->Name = Male
              ->Value = 20
             Banner 2
              ->Name = Famales
              ->Value = 20
   ->Question 2
     ->Text = Question Two
     ->Filters
     ......
     .....
     ....
     ...

因为我只能逐行读取数据库，所以我需要找到一种方法来在问题/过滤器组合中添加每个新的横幅和值。最后我想把它吐出来作为一个表格，其中每个横幅都是一列。

Answer 1

首先，你需要三个类

class Question {
   var $text;
   var $filters;
}

class Filter {
   var $name;
   var $banners;
}

class Banner {
   var $name;
   var $value;
}

然后您将开始创建您的问题并向其添加过滤器和横幅，如下所示:

$questions = array();
$x = 0;
$result = mysql_query("SELECT * FROM `questions`");
while ($obj = mysql_fetch_object($result)) {
    $questions[$x] = new Question();
    $questions[$x]->text = $obj->text;
    $result2 = mysql_query("SELECT * FROM `filters` WHERE `question` = {$obj->id}");
    $questions[$x]->filters = array();
    $y = 0;
    while ($obj2 = mysql_fetch_object($result2)) {
        $questions[$x]->filters[$y] = new Filter();
        ...
        // and so on
        ...
        $y++;
    }
    $x++;
}

希望对您有所帮助。