php - 警告 : mysql_result() [function. mysql-result] : Unable to jump to row 0 on MySQL result index 5 in profile. php on line 11

Question

当我尝试访问 profile.php?u=destiny

//$result = mysql_query('SELECT name FROM 
$imageresult = mysql_query("SELECT name FROM imagetable WHERE id = '$id'") or die(mysql_error());
$u = mysql_result($imageresult, 0 ,"name") or die(mysql_error());
//error_reporting(E_ALL);
if (isset($id) && (!isset($u))) {
}

Warning: mysql_result() [function.mysql-result]: Unable to jump to row 0 on MySQL result index 5 in profile.php on line 11

Answer 1

此警告意味着 $imageresult 变量中没有行。检查一下，这应该有效:

$imageresult = mysql_query("SELECT name FROM imagetable WHERE id = '$id'") or die(mysql_error());
if (mysql_num_rows($imageresult) > 0) {
  $u = mysql_result($imageresult, 0 ,"name") or die(mysql_error());
  if (isset($id) && (!isset($u))) {
  }
}