如果只有一个命名的占位符用于准备好的语句,我目前编写的代码可以正常工作,但如果查询有多个条件,它不会从数据库返回任何结果。
例如:
$query = array();
$query['columns'] = array('*');
$query['tables'] = array('esl_comments');
$query['where'] = array(
'esl_comments.commentVisible' => array('=', 'Y')
);
工作正常。但如果我尝试:
$query = array();
$query['columns'] = array('*');
$query['tables'] = array('esl_comments');
$query['where'] = array(
'esl_comments.commentVisible' => array('=', 'Y'),
'esl_comments.commentID' => array('=', '1'),
);
(注意附加的 commentID 参数)尽管 mySQL 数据库中有满足条件的数据,但它无法返回任何内容。
我写的PDO代码是:
$sql ='SELECT ';
foreach($query['columns'] as $column){ //What columnns do we want to fetch?
$sql.=$column . ", ";
}
$sql = rtrim($sql, " ,");
$sql .=' FROM '; //Which tables will we be accessing?
foreach($query['tables'] as $tables){
$sql.=$tables . ", ";
}
$sql = rtrim($sql, " ,"); //Get rid of the last comma
$sql .=' WHERE ';
if(array_key_exists('where', $query)) //check if a where clause was provided
{
$fieldnames = array_keys($query['where']);
$count = 0;
$size = sizeof($fieldnames);
$bindings = array();
foreach($query['where'] as $where){
$cleanPlaceholder = str_replace("_", "", $fieldnames[$count]);
$cleanPlaceholder = str_replace(".", "", $cleanPlaceholder);
$sql.=$fieldnames[$count].$where[0].":".$cleanPlaceholder." AND ";
$bindings[$cleanPlaceholder]=$where[1];
$count++;
}
$sql = substr($sql, 0, -5); //Remove the last AND
}
else{ //no where clause so set it to an always true check
$sql.='1=1';
$bindings=array('1'=>'1'); //Provide default bindings for the statement
}
$sql .= ';'; //Add the semi-colon to note the end of the query
echo $sql . "<br/><br/>";
// exit();
$stmt = $this->_connection->prepare($sql);
foreach($bindings as $placeholder=>$bound){
echo $placeholder . " - " . $bound."<br/>";
$stmt->bindParam($placeholder, $bound);
}
$result = $stmt->execute();
echo $stmt->rowCount() . " records<br/>";
$results = $stmt->fetchAll(PDO::FETCH_ASSOC);
我正在动态构建查询,因此我通过去除句号和下划线来清理占位符 - 因此使用了“cleanPlaceholder”变量。
正在生成的查询如下所示:
SELECT * FROM esl_comments WHERE esl_comments.commentVisible=:eslcommentscommentVisible AND esl_comments.commentID=:eslcommentscommentID;
被绑定(bind)的参数是这样的:
eslcommentscommentVisible - Y
eslcommentscommentID - 1
最佳答案
bindParam 需要引用
问题是由您在 foreach 循环中绑定(bind)参数的方式引起的。
foreach($bindings as $placeholder=>$bound){
echo $placeholder . " - " . $bound."<br/>";
$stmt->bindParam($placeholder, $bound);
}
bindParam
需要引用。它将变量而不是值绑定(bind)到语句。由于 foreach 循环中的变量在每次迭代开始时被重置,因此只有最后一个对 $bound
的引用保持不变,您最终将所有占位符绑定(bind)到它。
这就是为什么您的代码在 $query['where']
仅包含一个条目时有效,但在包含多个条目时失败的原因。
您可以通过两种方式解决问题:
通过引用传递
foreach($bindings as $placeholder => &$bound) { //pass $bound as a reference (&)
$stmt->bindParam($placeholder, $bound); // bind the variable to the statement
}
按值传递
使用bindValue
代替bindParam
:
foreach($bindings as $placeholder => $bound) {
$stmt->bindValue($placeholder, $bound); // bind the value to the statement
}
关于php - PDO 多个命名占位符不检索数据,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/13667807/