首先我会说我是编码新手，所以我觉得这很困难，最近我也问了几个问题，主要是因为我真的被困住了，所以非常感谢所有帮助。
我有两张 table 。员工(Employee_ID、First_name、Last_name、地址等)和培训(Training_ID、Employee_ID、First_name、Last_name、Training_type)。
对于培训表，我有一个表格，要填写该表格以为员工分配培训类型。
好的，目前，员工 ID 的下拉框具有来自员工表的员工 ID 的值。
当我从下拉框中选择一个值时，我希望表单中的文本字段(名字和姓氏)更新以显示该 employee_id 的名称。我在网上搜索过，但不知道该怎么做。
下面显示了我的表单(php)
<html>
<?php
$con = mysql_connect("localhost","root","");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db("hrmwaitrose", $con);
?>
<head>
<link type="text/css" rel="stylesheet" href="style.css"/>
<title>Training</title>
</head>
<body>
<div id="content">
<h1 align="center">Add Training</h1>
<form action="inserttraining.php" method="post">
<div>
<p>Training ID: <input type="text" name="Training_ID"></p>
<p>Employee ID:<select id="Employee_ID">
<?php
$result = mysql_query("SELECT Employee_ID FROM Employee");
while ($row = mysql_fetch_row($result)) {
echo "<option value=$row[0]>$row[0]</option>";
}
?>
</select>
<p>First name: <input type="text" name="First_name"></p>
<p>Last name: <input type="text" name="Last_name"></p>
<p>
Training required?
<select name="Training">
<option value="">Select...</option>
<option value="Customer Service">Customer Service</option>
<option value="Bailer">Bailer</option>
<option value="Reception">Reception</option>
<option value="Fish & meat counters">Fish & meat counters</option>
<option value="Cheese counters">Cheese counters</option>
</select>
</p>
<input type="submit">
</form>
</div>
</body>
</html>
这是我按下提交按钮时的 php 代码。
<?php
$con = mysql_connect("localhost","root","");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db("hrmwaitrose", $con);
$sql="INSERT INTO training (Training_ID, Employee_ID, First_name, Last_name, Training)
VALUES
('$_POST[Training_ID]','$_POST[Employee_ID]','$_POST[First_name]','$_POST[Last_name]','$_POST[Training]')";
if (!mysql_query($sql,$con))
{
die('Error: ' . mysql_error());
}
echo "1 record added";
mysql_close($con);
?>
我认为它是由 java 完成的？不太确定。
最佳答案
您的 View 文件:
<?php
// First of all, don't make use of mysql_* functions, those are old
$pdo = new PDO("mysql:host=localhost;dbname=hrmwaitrose;charset=utf8", "root", "");
?>
<html>
<head>
<link type="text/css" rel="stylesheet" href="style.css"/>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1/jquery.min.js"></script> <!-- You will need jQuery (or anyother javascript framework) to accomplish your goal cause you need ajax -->
<title>Training</title>
</head>
<body>
<div id="content">
<h1 align="center">Add Training</h1>
<form action="inserttraining.php" method="post">
<div>
<p>
Training ID:
<input type="text" name="Training_ID">
</p>
<p>
Employee ID:
<select id="Employee_ID">
<option value="">Select one</option>
<?php
$st = $pdo->prepare("SELECT Employee_ID FROM Employee");
$st->execute();
$rows = $st->fetchAll(PDO::FETCH_ASSOC);
foreach ($rows as $row) {
?><option value="<?php echo $row ['Employee_ID']; ?>"><?php echo $row ['Employee_ID']; ?></option><?php
}
?>
</select>
<p>
First name:
<input type="text" name="First_name" id="First_name">
</p>
<p>
Last name:
<input type="text" name="Last_name" id="Last_name">
</p>
<p>
Training required?
<select name="Training">
<option value="">Select...</option>
<option value="Customer Service">Customer Service</option>
<option value="Bailer">Bailer</option>
<option value="Reception">Reception</option>
<option value="Fish & meat counters">Fish & meat counters</option>
<option value="Cheese counters">Cheese counters</option>
</select>
</p>
<input type="submit">
</form>
</div>
<script type="text/javascript">
$(function() { // This code will be executed when DOM is ready
$('#Employee_ID').change(function() { // When the value for the Employee_ID element change, this will be triggered
var $self = $(this); // We create an jQuery object with the select inside
$.post("getEmployeeData.php", { Employee_ID : $self.val()}, function(json) {
if (json && json.status) {
$('#First_name').val(json.name);
$('#Last_name').val(json.lastname);
}
})
});
})
</script>
</body>
</html>
您的 getEmployeeData.php 文件:
<?php
$pdo = new PDO("mysql:host=localhost;dbname=hrmwaitrose;charset=utf8", "root", "");
header("Content-Type:application/json; Charset=utf-8");
// As you can see, here you will have where Employee_ID = :employee_id, this will be
// automatically replaced by the PDO object with the data sent in execute(array('employee_id' => $_POST['Employee_ID']))
// This is a good practice to avoid SqlInyection attacks
$st = $pdo->prepare("SELECT First_name, Last_name FROM Employee WHERE Employee_ID = :employee_id");
$st->execute(array ('employee_id' => $_POST['Employee_ID']));
$data = $st->fetch(PDO::FETCH_ASSOC);
echo json_encode(array ('status' => true, 'name' => $data ['First_name'], 'lastname' => $data ['Last_name']));
一些最后的建议:正确缩进代码。关闭每个 html 标签(例如 <input />)
关于php - 根据从动态下拉框中选择的值预填充文本字段(在表单中)，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/15160395/