我想弄清楚如何更新特定数据库行中的数据，而不是删除然后再次插入另一个查询。有谁知道我该怎么做？
main.php 内容
<body>
<h1>Introduction Box</h1>
<form action="edit.php" method="post">
Title: <input type="text" name="introtitle">
Description: <textarea name="introdescription"></textarea>
<input type="submit">
</form>
</body>
edit.php 内容(现在这只会添加表单中的条目)
<?php
// Connnection to MySQL
$connection = mysqli_connect("");
// Check Connection and Display If Error
if (mysqli_connect_errno($connection)) {
echo "Failed to connect to MySQL: " . mysqli_conncet_error();
}
$introduction="INSERT INTO Introduction (Title, Description)
VALUES ('$_POST[introtitle]','$_POST[introdescription]')";
if (!mysqli_query($connection, $introduction) or die(mysql_error()))
{
die('Error: ' . mysqli_error($connection));
}
echo "Record has been updated.";
mysqli_close($connection);
?>
任何帮助将不胜感激!
最佳答案
html 表单代码看起来像
<h1>Introduction Box</h1>
<form action="edit.php" method="post">
Title: <input type="text" name="introtitle">
Description: <textarea name="introdescription"></textarea>
<input type="hidden" name="id" value="<?php echo $current_edit_id;?>">
<input type="submit">
</form>
</body>
php 脚本代码看起来像
<?php
// Connnection to MySQL
$connection = mysqli_connect("");
$current_edit_id = $_POST['current_edit_id'];
// Check Connection and Display If Error
if (mysqli_connect_errno($connection)) {
echo "Failed to connect to MySQL: " . mysqli_conncet_error();
}
$introduction="UPDATE Introduction SET Title='value', Description='value' WHERE ID='$current_edit_id'";
if (!mysqli_query($connection, $introduction) or die(mysql_error()))
{
die('Error: ' . mysqli_error($connection));
}
echo "Record has been updated.";
mysqli_close($connection);
?>
希望这一定能帮到你。
关于php - 如何使用替换行中的现有数据？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/17871929/