MYSQL:根据一个表的范围连接两个表

Question

我有两个表

员工工资

   salary_id  emp_id  salary
    1         1       51000
    2         2       30000
    3         3       40000
    4         4       20000
    5         5       64000
    6         6       47000
    7         7       98000

员工表结构

emp_id |    first_name | last_name |    gender  | email | mobile  | dept_id  | is_active

给定的薪水是

salary < 50000 as L
 70000 < salary > 50000 as M
salary > 70000 as H

According to salary slab list out the employee who fall in which salary slab 

Answer 1

SELECT *, 
   CASE
      WHEN salary < 50000 THEN 'L'
      WHEN salary BETWEEN 50000 AND 70000 THEN 'M'
      ELSE  'H'
   END CASE AS slab
FROM employee_salary

加入员工表以获取姓名/个人信息作为练习留给读者。