我正在运行 MySQL 查询来搜索作业数据库。我使用 MATCH 和 AGAINST 来对结果进行相关排序。 然而,我很困惑为什么这两个查询返回不同的结果:
SELECT SQL_CALC_FOUND_ROWS *, MATCH (`title`)
AGAINST ("assistant")
AS Relevance
FROM jobs2
WHERE MATCH (`title`)
AGAINST ("assistant") AND date >= CURDATE() - INTERVAL 28 DAY GROUP BY jobref ORDER BY Relevance DESC LIMIT 0,50
据我了解,它将默认为自然语言模式,但返回 0 结果,而:
SELECT SQL_CALC_FOUND_ROWS *, MATCH (`title`)
AGAINST ("assistant" IN BOOLEAN MODE)
AS Relevance
FROM jobs2
WHERE MATCH (`title`)
AGAINST ("assistant" IN BOOLEAN MODE) AND date >= CURDATE() - INTERVAL 28 DAY GROUP BY jobref ORDER BY Relevance DESC LIMIT 0,50
按预期返回 4 个结果,但相关性始终为 1,因此实际上不可能按相关性排序?
我的数据库有以下测试作业:
|date |title |jobref|
|2016-04-08 07:21:19|Assistant Management Accountant |12345 |
|2016-04-08 07:21:19|Assistant Accountant |12346 |
|2016-04-08 07:19:15|Assistant Finance Manager |12347 |
|2016-04-08 07:20:38|Accounts Assistant / Purchase Ledger Clerk / Accounts Payable |12348 |
基本上,为什么自然语言模式返回 0 个结果?
最佳答案
来自自然语言搜索的 MySQL 文档:
In addition, words that are present in 50% or more of the rows are considered common and do not match.
http://dev.mysql.com/doc/refman/5.5/en/fulltext-search.html
看来您的样本数据超过了 50% 的匹配率。
关于mysql - 为什么这 2 个 MySQL 查询返回不同的结果,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/36508972/