php - 我可以将几个查询替换为一个吗

Question

我有一些查询调用，我想将其替换为一个，但我不知道这是否可行。我的数据库看起来像:

我的数据库调用:

$minbet = $mysql->query('SELECT `value` FROM `jackpot1_info` WHERE `name`="minbet"')->fetch_assoc();
$minbet =  $minbet['value'];

$maxbet = $mysql->query('SELECT `value` FROM `jackpot1_info` WHERE `name`="maxbet"')->fetch_assoc();
$maxbet =  $maxbet['value'];

$maxitems = $mysql->query('SELECT `value` FROM `jackpot1_info` WHERE `name`="maxitems"')->fetch_assoc();
$maxitems =  $maxitems['value'];

$maxitemsinpot = $mysql->query('SELECT `value` FROM `jackpot1_info` WHERE `name`="maxitemsinpot"')->fetch_assoc();
$maxitemsinpot =  $maxitemsinpot['value'];

Answer 1

很简单，只需在单个查询中选择name 和value，您将获得每个name 和value 在单独的行中配对:

$select = $mysql->query('
    SELECT `name`, `value`
    FROM `jackpot1_info`
    WHERE `name` IN ("minbet","maxbet","maxitemsinpot","maxitems")
');

while ($result = $mysql->fetch_assoc())
{
    var_dump($result);
}

输出看起来像:

array(2) {
  'name' =>
  string(12884901894) "minbet"
  'value' =>
  int(123)
}

array(2) {
  'name' =>
  string(12884901894) "maxbet"
  'value' =>
  int(456)
}

...

我相信您可以完成剩下的工作。