我正在尝试在单个查询中更新多行。数据没有在我的代码中更新。我正在尝试加入这两个表。当用户输入编号时。将显示通过外键连接的 2 个表中的数据。表 1 中的数据得到更新。表 2 中的列没有更新。我需要根据唯一 id 更新第二个表
if($_REQUEST["profile"] == "profile")
{
$Id = $_REQUEST["id"];
$firstname = mysql_real_escape_string($_REQUEST["firstname"]);
$serial = mysql_real_escape_string($_REQUEST["serial"]);
$dom = mysql_real_escape_string($_REQUEST["dom"]);
$idno = $_REQUEST["idno"];
$pow = mysql_real_escape_string(stripslashes($_REQUEST["pow"]));
$address = mysql_real_escape_string(stripslashes($_REQUEST["address"]));
$bookno = mysql_real_escape_string(stripslashes($_REQUEST["bookno"]));
$zone = mysql_real_escape_string(stripslashes($_REQUEST["zone"]));
$mobile = mysql_real_escape_string(stripslashes($_REQUEST["phone"]));
$phone = mysql_real_escape_string(stripslashes($_REQUEST["mobile"]));
$mothertongue=mysql_real_escape_string(stripslashes($_REQUEST["mothertongue"]));
$nof=mysql_real_escape_string(stripslashes($_REQUEST["nof"]));
$email=mysql_real_escape_string(stripslashes($_REQUEST["email"]));
$nom=$_REQUEST["nom"];
$nofemale=$_REQUEST["nofemale"];
mysql_query("UPDATE profile SET firstname='".$firstname."',serial='".$serial."',dom='".$dom."',idno='".$idno."',pow='".$pow."',address='".$address."',bookno='".$bookno."',
zone='".$zone."',phone='".$mobile."',mobile='".$phone."',mothertongue='".$mothertongue."',email='".$email."',nof='".$nof."',nom='".$nom."',nofemale='".$nofemale."' WHERE id = '".$_POST['id']."' " ) or die(mysql_error());
for($i=0;$i<count($_REQUEST['slno1']);$i++)
{
$mid=$_REQUEST['mid'][$i];
$slno1 = mysql_real_escape_string(stripslashes($_REQUEST["slno1"][$i]));
$name1 = mysql_real_escape_string(stripslashes($_REQUEST["name1"][$i]));
$rhof1 = mysql_real_escape_string(stripslashes($_REQUEST["rhof1"][$i]));
$dob1 = mysql_real_escape_string(stripslashes($_REQUEST["dob1"][$i]));
$dobapt1 = mysql_real_escape_string(stripslashes($_REQUEST["dobapt1"][$i]));
$doc1 = mysql_real_escape_string(stripslashes($_REQUEST["doc1"][$i]));
$doconf1 = mysql_real_escape_string(stripslashes($_REQUEST["doconf1"][$i]));
$qualification1 = mysql_real_escape_string(stripslashes($_REQUEST["qualification1"][$i]));
$school1 = mysql_real_escape_string(stripslashes($_REQUEST["school1"][$i]));
$occupation1 = mysql_real_escape_string(stripslashes($_REQUEST["occupation1"][$i]));
$run=mysql_query("UPDATE member SET
slno1='".$slno1."',name1='".$name1."',rhof1='".$rhof1."',dob1='".$dob1."',dobapt1='".$dobapt1."',doc1='".$doc1."',doconf1='".$doconf1."',qualification1='".$qualification1."' WHERE mid = '".$mid."' " ) or die(mysql_error());
}
}
最佳答案
请使用 PDO，这样您就不必对字符串进行转义，从而使您的代码更易于阅读。您的查询使用了太多引号，仅此一项就很容易失败。请使用以下示例，这应该可以帮助您取得成功。
基本 PDO 更新: https://www.w3schools.com/php/php_mysql_update.asp
绑定(bind)参数: https://www.w3schools.com/php/php_mysql_prepared_statements.asp
关于php - 在单个查询php mysql中更新多行，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/50445906/