我的代码有问题。显示具有 n 个子类别的所有类别的最佳方式是什么?
我的 MySQL 数据库如下所示:
CREATE TABLE categories (
category_id INT UNSIGNED NOT NULL AUTO_INCREMENT,
parent_id INT UNSIGNED NOT NULL DEFAULT 0,
name TEXT NOT NULL,
user INT NOT NULL,
PRIMARY KEY (category_id),
INDEX parent (parent_id)
);
其中 user
是来自另一个表的 id(如果类别有 user = '2'
,id = '2'
的用户可以看到那个类别)
category_id parent_id name user
1 0 Main category 1 2
2 1 Subcategory 1 2
3 1 Subcategory 2 2
4 3 SubSubcategory 1 2
我的 php 代码:
<?php
include('config.php'); //Mysql connect file
//get id from user
if($_GET['id'] != $user_id) {
$id = $_GET['id'];
//check to make sure the user is an admin, who can change mysql
$result = mysql_query("SELECT * FROM users WHERE username = '$username' AND admin = '1'");
$rowCheck = mysql_result($result, 0);
//if the query returns a number, we know the user is an admin. And here we can VIEW our categories
if($rowCheck > 0) {
$user_result = mysql_query("SELECT * FROM users, categories WHERE id = '$id'");
while($row = mysql_fetch_array($user_result)) { ?>
<ol>
<li><a href=""><?php echo $row['name']; ?></a></li>
</ol>
<?php }
} else {
echo "You are not admin";
}
//bla bla bla etc.
...
}
如何查看类
<ol>
<li>
<a href="">Main category 1</a>
<ol>
<li><a href="">Subcategory 1</a></li>
<li><a href="">Subcategory 2</a>
<ol>
<li><a href="">Subsubcategory 1</a></li>
</ol>
</li>
</ol>
</li>
</ol>
最佳答案
试试这个
$result = mysql_query("SELECT * FROM users WHERE username = '$username' AND admin = '1'");
$rowCheck = mysql_result($result, 0);
//if the query returns a number, we know the user is an admin. And here we can VIEW our categories
if($rowCheck > 0) {
//First fetch only parent categories
$first_level_cats = mysql_query("SELECT * FROM categories WHERE user = '$id' AND parent_id = 0");
echo '<ol>';
while($row = mysql_fetch_array($first_level-cats)) { ?>
<li><a href=""><?php echo $row['name']; ?></a></li>
<?php
$second_level_cats = mysql_query("SELECT * FROM categories WHERE user = '$id' AND parent_id = $row['id']");
echo '<ol>';
while($row = mysql_fetch_array($second_level-cats)) { ?>
<li><a href=""><?php echo $row['name']; ?></a></li>
<?php
$third_level_cats = mysql_query("SELECT * FROM categories WHERE user = '$id' AND parent_id = $row['id']");
echo '<ol>';
while($row = mysql_fetch_array($sthird_level-cats)) { ?>
<li><a href=""><?php echo $row['name']; ?></a></li>
<?php
}
echo '</ol>'; //third level close
?>
}
echo '</ol>'; // second level close
?>
<?php }
echo '</ol>'; // first level close
} else {
echo "You are not admin";
}
//bla bla bla etc.
...
}
我已尽力解决您的查询,根据您的架构
交叉检查表名和列
。
关于php - 使用 PHP+MySQL 显示带有子类别和 n-sub 类别的类别,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/17164165/