mysql - 如何使用 Sequel Pro 创建触发器

Question

我正在尝试在数据库上创建触发器。我可以让它在 SQL fiddle 中正常工作，但是当我尝试在 Sequal Pro 中创建触发器时，我只是得到一个错误..

You have an error in your SQL syntax; check the manual that corresponds to your MySQL 
server version for the right syntax to use near '' at line 8

这是 SQL fiddle.. http://sqlfiddle.com/#!2/e849f/1

我使用的过程是在创建模式后在查询窗口中执行以下命令..

CREATE TRIGGER upd_selectoin 
BEFORE UPDATE ON main 
FOR EACH ROW 
BEGIN
   IF NEW.state = 3 THEN 
   UPDATE selection s JOIN main m 
      ON m.main_id = s.id
      SET s.allow = 1, last_update_timestamp = NOW()
   WHERE s.id = NEW.main_id; 
 END IF;
END; 

Answer 1

遇到同样问题的人:

Sequel Pro 自行创建周围语句。 所以声明应该是这样的:

IF NEW.state = 3 THEN 
  UPDATE selection s JOIN main m 
    ON m.main_id = s.id
    SET s.allow = 1, last_update_timestamp = NOW()
  WHERE s.id = NEW.main_id;
END IF;