mysql - 从结果中选择

Question

我有一张 table

scores(user, score)

我有这个问题

SET @row_num = 0; 
SELECT @row_num := @row_num + 1 as row_index, user, score 
FROM scores ORDER BY score DESC

现在我想从这个查询结果中选择名称为“john”且得分为“1400”的用户，以了解他的 row_index 是什么，例如

SELECT row_index 
FROM *result* WHERE user='john' AND score=1400

我该怎么做？我试过了

SET @row_num = 0; 
SELECT row_index 
FROM (SELECT @row_num := @row_num + 1 as row_index, user, score 
      FROM scores ORDER BY score DESC)      
WHERE user='john' AND score=1400`

但是 phpMyAdmin 说

#1248 - Every derived table must have its own alias

我该怎么做？

谢谢， 亚历山德罗

Answer 1

您还没有为派生表添加别名。

SELECT row_index FROM (...) AS alias
WHERE alias.user = 'john' AND alias.score = 1400