前段时间我有一个问题如何用多个count()
写一个sql查询,and got needed answer here .
现在假设我有完全相同的表
ID|group_name|username
----------------------
1 | A | user1
----------------------
2 | B | user2
----------------------
3 | C | user1
...
和完全相同的查询:
select count(*) from TABLE
where username='user1'
having (sum(group_name ='A') > 0
and sum(group_name = 'B') > 0)
or sum(group_name = 'C') > 0")
但现在我不想统计,而是列出所有与这个having
语句对应的用户名。即列出所有同时在A 和B 或C 组中的用户名。
目前我只尝试将 count(*)
替换为 username
并在我的查询中添加 group by username
,像这样:
select username where username='user1' having (sum(group_name ='A') > 0 and sum(group_name = 'B') > 0) or sum(group_name = 'C') > 0") group by username
但是我得到语法错误:
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'GROUP BY
username
LIMIT 0, 25' at line 1
非常感谢任何形式的帮助。
最佳答案
要列出满足您条件的用户名,您可以将查询写为
select username
from table
group by username
having (
sum(group_name ='A') > 0 and sum(group_name = 'B') > 0
) or sum(group_name = 'C') > 0
关于MySql 列出总和 > 0 的所有字段,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/50482129/