我有一个食谱表:
CREATE TABLE IF NOT EXISTS `RECIPES` (
`recipes_id` int(11) NOT NULL AUTO_INCREMENT,
`title` varchar(50) CHARACTER SET utf8 COLLATE utf8_bin NOT NULL,
`text` varchar(2000) CHARACTER SET utf8 COLLATE utf8_bin NOT NULL,
`count_persons` int(11) NOT NULL,
`duration` int(11) NOT NULL,
`user_id` int(11) NOT NULL,
`date` datetime NOT NULL,
`accepted` int(11) NOT NULL DEFAULT '0',
PRIMARY KEY (`recipes_id`),
KEY `recipes_user_fk` (`user_id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=44 ;
插入:
(20, 'Hundefutter', 'Dose öffnen', 4, 10, 1, '2011-12-31 23:59:5', 0)
我用 php 将它解析为 json (getByID):
<?php
header('Content-Type: text/html; charset=utf8');
$id = $_GET['id'];
include 'db_connect.php';
$arr = array('Data' => null,'Message' => null,'Code' => null);
if (is_numeric($id))
{
//include 'db_connect.php';
$id = mysql_real_escape_string($_GET['id']);
mysql_query("SET NAMES 'utf8'");
mysql_query("SET CHARACTER SET 'utf8'");
$sql = "Select * from RECIPES WHERE recipes_id=".$id;
$result = mysql_query($sql,$db) or exit("QUERY FAILED!");
while($row = mysql_fetch_array($result))
{
$arr['Data']['Recipes']['Recipe_'.$row['recipes_id']]['ID'] = $row['recipes_id'];
$arr['Data']['Recipes']['Recipe_'.$row['recipes_id']]['TITLE'] = $row['title'];
$arr['Data']['Recipes']['Recipe_'.$row['recipes_id']]['TEXT'] = utf8_decode($row['text']);
$arr['Data']['Recipes']['Recipe_'.$row['recipes_id']]['COUNT_PERSONS'] = $row['count_persons'];
$arr['Data']['Recipes']['Recipe_'.$row['recipes_id']]['DURATION'] = $row['duration'];
$arr['Data']['Recipes']['Recipe_'.$row['recipes_id']]['USER_ID'] = $row['user_id'];
$arr['Data']['Recipes']['Recipe_'.$row['recipes_id']]['DATE'] = $row['date'];
}
if(count($arr['Data']['Recipes'])==1)
{
$arr['Code'] = 200;
}
else
{
$arr['Code'] = 404;
$arr['Message'] = "not found";
}
}
else
{
$arr['Code'] = 400;
$arr['Message'] = "Bad Request";
}
mysql_close($db);
echo json_encode($arr);
?>
我的问题是当我调用 getRecipeByID.php?=20:
{"Data":{"Recipes":{"Recipe_20":{"ID":"20","TITLE":"Hundefutter","TEXT":"Dose \u00f6ffnen","COUNT_PERSONS":"4","DURATION":"10","USER_ID":"1","DATE":"2011-12-31 23:59:59"}}},"Message":null,"Code":200}
我得到 'ö' 作为字符代码。
如何解决这个问题?
谢谢
最佳答案
I get the 'ö' as char code. How to solve this problem?
你不知道。 \u00f6
是 JSON 中完全合法的字符转义码。解析 JSON 后,它将解析为 ö
。
关于php - PHP 中的元音编码错误,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/8266465/