mysql - 在mysql中合并两个表

Question

我有三个表

   table name: tags
          id (int)
          tag_name (vharchar)    

   table name: messages
          id (int)
          message_title (vharchar)
          message_content(vharchar)

    table name: message_tag
          message_id (int)
          tag_id (int)

我试过这段代码，但它没有用(返回空)

SELECT messages.message_title, messages.message_content, tags.tag_name
            FROM messages
            INNER JOIN message_tag ON messages.id = message_tag.message_id
            INNER JOIN tags ON tags.id = message_tag.tag_id
            WHERE message_tag.tag_id =191
            AND message_tag.tag_id =19
            AND message_tag.tag_id =31
            ORDER BY RAND( )
            LIMIT 20

我想随机选择 20 行连接到标签 191、19 和 31

Answer 1

SELECT messages.message_title, messages.message_content, tags.tag_name
        FROM messages
        INNER JOIN message_tag ON messages.id = message_tag.message_id
        INNER JOIN tags ON tags.id = message_tag.tag_id
        WHERE message_tag.tag_id IN (191, 19, 31)
        ORDER BY RAND( )
        LIMIT 20

使用 IN 而不是 AND。这将为您带来至少链接到这些特定标签之一的消息。

更新:如果您想要获取所有 3 个标签都存在的消息，您可以改为这样做(假设您在 message_tag 中的行是唯一的):

    SELECT messages.message_title, messages.message_content, tags.tag_name
        FROM messages
        INNER JOIN message_tag ON messages.id = message_tag.message_id
        INNER JOIN tags ON tags.id = message_tag.tag_id
        WHERE message_tag.tag_id IN (191, 19, 31)
        GROUP BY messages.id
        HAVING COUNT(messages.id) > 2
        ORDER BY RAND( )
        LIMIT 20