php - 查询AS时mysql查询报错

Question

这个查询对我来说很好用:

$query = "
         SELECT 
           p.topnode_id,
           p.param_key,
           p.param_value 
         FROM
           tbl_params p
         INNER JOIN
           tbl_clients c
         ON
           c.client_id = p.client_id
         WHERE
           p.client_id = ?
         ";

但是，如果我将 AS 放入查询中，它会抛出一个错误:

$query = "
         SELECT 
           p.topnode_id AS topnode_id,
           p.param_key AS key,
           p.param_value AS value
         FROM
           tbl_params p
         INNER JOIN
           tbl_clients c
         ON
           c.client_id = p.client_id
         WHERE
           p.client_id = ?
         ";

似乎是什么问题？

Answer 1

key是Mysql的保留字，需要用反引号转义

as `key`