MySQL 没有捕捉到错误

Question

当我尝试删除不存在的行时，为什么这段代码没有捕捉到错误？无论我将什么参数作为行名传入，它总是返回“1 行已删除”并且不使用退出处理程序。应该只捕获这种类型的错误。

USE yoga;

DROP PROCEDURE IF EXISTS delete_warmup;

DELIMITER //

CREATE PROCEDURE delete_warmup 
(
    warmup_name_param               VARCHAR(100)
)
BEGIN
DECLARE row_not_found       TINYINT DEFAULT FALSE;
DECLARE sql_exception       TINYINT DEFAULT FALSE;

BEGIN
    DECLARE EXIT HANDLER FOR 1329
        SET row_not_found = TRUE;
    DECLARE EXIT HANDLER FOR SQLEXCEPTION
        SET sql_exception = TRUE;

    DELETE FROM warmup
    WHERE warmup_name = warmup_name_param;

    SELECT '1 row was deleted.' AS message;
END;

IF row_not_found = TRUE THEN
    SELECT 'Row not deleted - row not found' AS message;
ELSEIF sql_exception = TRUE THEN
    SHOW ERRORS;
END IF;

END//

DELIMITER ;

CALL delete_warmup ('Monkey business');

Answer 1

您正在为重复参数使用退出处理程序:http://www.briandunning.com/errors/596这是你指定的 1329

也许您应该尝试错误代码 1011:http://www.briandunning.com/errors/278

此外，尝试查找 NOT FOUND 以及 SQLException

此外，尝试将退出处理程序放在开始/结束子句之外。

因此您的BEGIN 和END 子句将是

DECLARE EXIT HANDLER FOR 1011
DECLARE EXIT HANDLER FOR SQLEXCEPTION, NOT FOUND
BEGIN
        SET row_not_found = TRUE;
        SET sql_exception = TRUE;

    DELETE FROM warmup
    WHERE warmup_name = warmup_name_param;

    SELECT '1 row was deleted.' AS message; 
END;