mysql - 使用 group by 每 2 分钟对数据进行一次分组

Question

我有一个数据库可以找到每分钟的总位数，并使用 group by 语句对它们进行分组。我想知道，如何使用相同的 group by 语句对每 2 分钟的 totalBits 进行分组和求和？

这是我每分钟分组的一组查询

SELECT SUM(totalBits ) AS totalBits,
EXTRACT( YEAR FROM timeStampID ) AS YEAR,
EXTRACT( MONTH FROM timeStampID ) AS MONTH ,
EXTRACT( DAY FROM timeStampID ) AS DAY ,
EXTRACT( HOUR FROM timeStampID ) AS HOUR ,
EXTRACT( MINUTE FROM timeStampID ) AS MINUTE ,
EXTRACT( SECOND FROM timeStampID ) AS SECOND FROM  `ipByteReceive1`
WHERE  `timeStampID` >  '2013-01-21 08:58:55'
GROUP BY YEAR, MONTH , DAY , HOUR, MINUTE

这是我得到的:

totalBits | YEAR | MONTH | DAY | HOUR | MINUTE
----------+------+-------+-----+------+--------
459       | 2013 | 1     | 21  | 8    | 58
2         | 2013 | 1     | 21  | 8    | 59
17        | 2013 | 1     | 21  | 9    | 00

这就是我想要得到的:

totalBits | YEAR | MONTH | DAY | HOUR | MINUTE
----------+------+-------+-----+------+--------
461       | 2013 | 1     | 21  | 8    | 58
17        | 2013 | 1     | 21  | 9    | 00

提前致谢!

Answer 1

只需更改提取分钟的方式，也以 2 为单位进行分组，然后去掉秒(因为它不再有任何意义)。

SELECT SUM(totalBits ) AS totalBits,
EXTRACT( YEAR FROM timeStampID ) AS YEAR, 
EXTRACT( MONTH FROM timeStampID ) AS MONTH ,
EXTRACT( DAY FROM timeStampID ) AS DAY , 
EXTRACT( HOUR FROM timeStampID ) AS HOUR , 
EXTRACT( MINUTE FROM timeStampID ) - MOD(EXTRACT( MINUTE FROM timeStampID ), 2) AS MINUTE , 
WHERE  `timeStampID` >  '2013-01-21 08:58:55'
GROUP BY YEAR, MONTH , DAY , HOUR, MINUTE