我正在使用我的 PHP 脚本来创建 XML 文档,这样我就可以生成 XML 文件以允许我将 XML 文件保存在我的 Web 主机中。
我想从 mysql 数据库中获取行列表,以在 xml 标记 channel
中输出每一行。
我想让 xml 输出看起来像这样:
<?xml version="1.0" encoding="UTF-8" ?>
<tv generator-info-name="www.mysite.com/xmltv">
<channel id="">
<display-name>Information from database</display-name>
<programme channel="Information from database" start="" stop="">
<title lang="en"></title>
<sub-title lang="en">
</sub-title>
<desc lang="en"></desc>
<category lang="en"></category>
</programme>
</channel>
这是 XML 输出:
<?xml version="1.0" encoding="UTF-8"?>
<tv generator-info-name="www.mysite.com/xmltv"/>
<channel><display-name>Information from database</display-name><programme/><desc/></channel>
这是 php:
<?php
function db_connect()
{
define('DB_HOST', 'localhost');
define('DB_USER', 'myusername');
define('DB_PASSWORD', 'mypassword');
define('DB_DATABASE', 'mydbname');
$errmsg_arr = array();
$errflag = false;
$link = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD);
if(!$link)
{
die('Failed to connect to server: ' . mysql_error());
}
$db = mysql_select_db(DB_DATABASE);
if(!$db)
{
die("Unable to select database");
}
}
db_connect();
function clean($var)
{
return mysql_real_escape_string(strip_tags($var));
}
$channels = clean($_GET['channels']);
$id = clean($_GET['id']);
if($errflag)
{
$_SESSION['ERRMSG_ARR'] = $errmsg_arr;
echo implode('<br />',$errmsg_arr);
}
else
{
$insert = array();
if(isset($_GET['channels']))
{
$insert[] = 'channels = \'' . clean($_GET['channels']) .'\'';
}
if(isset($_GET['id']))
{
$insert[] = 'id = \'' . clean($_GET['id']) . '\'';
}
if($channels && $id)
{
$qrytable1="SELECT id, channels, links FROM tvguide WHERE channels='$channels' && id='$id'";
$result1=mysql_query($qrytable1) or die('Error:<br />' . $qry . '<br />' . mysql_error());
echo '<?xml version="1.0" encoding="UTF-8" ?>
<tv generator-info-name="www.mysite.com/xmltv">
<channel id="">
<display-name></display-name>
<programme channel="" start="" stop="">
<title lang="en"></title>
<sub-title lang="en"></sub-title>
<desc lang="en"></desc>
<category lang="en"></category>
</programme>
</channel>
</tv>';
while ($row = mysql_fetch_array($result1))
{
}
mysql_close();
}
else if(!$channels && ! $id)
{
$qrytable1="SELECT id, channels, links, streams FROM tvguide";
$result1=mysql_query($qrytable1) or die('Error:<br />' . $qry . '<br />' . mysql_error());
while ($row = mysql_fetch_array($result1))
{
}
mysql_close();
}
}
// create a dom document with encoding utf8
$domtree = new DOMDocument('1.0', 'UTF-8');
// create a root element of the xml tree
$tv = $domtree->createElement('tv');
//create attributes for element
$generator_info_name = $domtree->createAttribute('generator-info-name');
$generator_info_name->value = 'mysite.com/xmltv';
//append attribute
$tv->appendChild($generator_info_name);
// append element to the doc
$tv = $domtree->appendChild($tv);
//add a channel as a child of the root
$channel = $domtree->createElement('channel');
$channel_id = $domtree->createAttribute('id');
$channel_id->value = '""';
$channel = $tv->appendChild($channel);
//append children to channel
$channel->appendChild($domtree->createElement('display-name','Information from database'));
$channel->appendChild($domtree->createElement("programme"));
$channel->appendChild($domtree->createElement('desc'));
//finally, save the file
echo $domtree->saveXML();
$domtree->save('myChannel.xml');
?>
能否请您告诉我如何更改每个 xml 标签:
<?xml version="1.0" encoding="UTF-8"?>
<channel>
<programme>
为了这个?
<?xml version="1.0" encoding="UTF-8" ?>
<channel id="">
<programme channel="" start="" stop="">
我想在我的代码中使用 DOMDocument 更改这些 xml 标记。
而且我还想知道如何为 mysql 数据库中的每一行创建每个 xml 标记?
最佳答案
将属性添加到 <programme>
中标签。你有这个
$channel->appendChild($domtree->createElement("programme"));
你需要把它改成这样
$programme = $domtree->createElement("programme");
$programme->setAttribute("channel", $channelInfo); // $channelInfo comes from database
$channel->appendChild($programme);
关于php - 如何使用 DOMDocument 更改 xml 源,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/22386620/