** 日程安排系统(按周预约的数量):**
我希望生成一个仪表板
,其中显示顾问列表以及他们在未来几周安排的预约数量。
因此,针对我的特定场景,我的 sql 查询/ Eloquent 等效查询如下:
select
consultant_id,
count(appointment) as num_appointments,
YEARWEEK(appointment, 1) as year_week
from
appointments
where
appointments.deleted_at is null
and appointments.consultant_id in (25, 29, 19, 38, 37, 32, 14, 21, 12, 40)
and appointment > '2014-12-07 16:39:07'
and YEARWEEK(now(), 1) + 4 >= YEARWEEK(appointment, 1)
group by consultant_id, YEARWEEK(appointment, 1)
order by consultant_id, YEARWEEK(appointment, 1) asc;
$consultants = $this->consultant
->with(['appointments' => function($q) {
$q->scheduled()
->where(\DB::raw('YEARWEEK(now(), 1) + 4'), '>=', \DB::raw('YEARWEEK(appointment, 1)'))
->select([
'consultant_id',
\DB::raw('count(appointment) as num_appointments'),
\DB::raw('YEARWEEK(appointment, 1) as year_week'),
])
->groupBy(\DB::raw('consultant_id, YEARWEEK(appointment, 1)'))
->orderBy(\DB::raw('consultant_id, YEARWEEK(appointment, 1)', 'DESC'));
}])
->orderBy('name')
->paginate(10);
这适用于每位顾问,如果有预约,它将提供如下信息:
consultant_id num_appointments year_week
14 5 201450
14 3 201451
29 4 201450
29 1 201451
40 1 201450
40 1 201452
但是,如果没有约会,则year_week 将丢失。
因此,在 mysql 中,然后在 Laravel 的查询生成器中,我希望能够将 year_week
行转置为列。这样表就会输出:
consultant_id week0 week1 week2
consultant_id 201450 201451 201452
14 5 3 NULL
29 4 1 NULL
40 1 NULL 1
更新
SELECT
consultant_id,
COUNT(CASE WHEN YEARWEEK(DATE_ADD(now(), INTERVAL 0 WEEK), 1) = YEARWEEK(appointment, 1) THEN 1 END) as this_week,
COUNT(CASE WHEN YEARWEEK(DATE_ADD(now(), INTERVAL 1 WEEK), 1) = YEARWEEK(appointmnet, 1) THEN 1 END) as week1,
COUNT(CASE WHEN YEARWEEK(DATE_ADD(now(), INTERVAL 2 WEEK), 1) = YEARWEEK(appointmnet, 1) THEN 1 END) as week2
FROM
demand as d
WHERE date_created >= DATE_SUB(CURDATE(), INTERVAL 3 MONTH)
GROUP BY consultant_id;
最佳答案
解决方案 1:在 spatie macro collection 中使用转置 ?
转置的目标是旋转多维数组,将行变成列,将列变成行。
collect([
['Jane', 'Bob', 'Mary'],
['<a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="177d76797257726f767a677b723974787a" rel="noreferrer noopener nofollow">[email protected]</a>', '<a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="61030e03210419000c110d044f020e0c" rel="noreferrer noopener nofollow">[email protected]</a>', '<a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="acc1cdded5ecc9d4cdc1dcc0c982cfc3c1" rel="noreferrer noopener nofollow">[email protected]</a>'],
['Doctor', 'Plumber', 'Dentist'],
]
)->transpose()->toArray();
// [
// ['Jane', '<a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="2a404b444f6a4f524b475a464f04494547" rel="noreferrer noopener nofollow">[email protected]</a>', 'Doctor'],
// ['Bob', '<a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="fe9c919cbe9b869f938e929bd09d9193" rel="noreferrer noopener nofollow">[email protected]</a>', 'Plumber'],
// ['Mary', '<a href="https://stackoverflow.com/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="2944485b50694c51484459454c074a4644" rel="noreferrer noopener nofollow">[email protected]</a>', 'Dentist'],
// ]
解决方案 2:使用 group by in collection groupBy 方法按给定键对集合的项目进行分组:
$collection = collect([
['account_id' => 'account-x10', 'product' => 'Chair'],
['account_id' => 'account-x10', 'product' => 'Bookcase'],
['account_id' => 'account-x11', 'product' => 'Desk'],
]);
$grouped = $collection->groupBy('account_id');
$grouped->toArray();
/*
[
'account-x10' => [
['account_id' => 'account-x10', 'product' => 'Chair'],
['account_id' => 'account-x10', 'product' => 'Bookcase'],
],
'account-x11' => [
['account_id' => 'account-x11', 'product' => 'Desk'],
],
]
*/
关于php - MYSQL/查询生成器/Eloquent - 将行转置为列,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/27348304/