我正在尝试在 mysql 中创建一个查询，以根据多列分配行号。以下是我需要所需结果的格式
CN PN GroupName WeekTimeReported rank desired_rank
X ProjX A 12/30/2013 1 1
X ProjX B 12/30/2013 2 1
X ProjX C 1/6/2014 3 2
X ProjX D 1/6/2014 4 2
Y ProjY A 1/13/2014 5 1
Y ProjY B 1/13/2014 6 1
Y ProjY C 1/20/2014 7 2
Y ProjY D 1/20/2014 8 2
Z ProjZ A 1/27/2014 9 1
Z ProjZ B 1/27/2014 10 1
Z ProjZ C 2/3/2014 11 2
Z ProjZ D 2/3/2014 12 2
我希望我的结果采用 desired_rank 列格式。因此，对于相同的 CN 和 PN，我想根据 WeekTimeReported 进行排名(我想查看项目进行的周数)。提前感谢您的帮助。
这是 SQLFiddle并查询:
SELECT
@cn:=ClientName ClientName
,ProjectName
,GroupName
,CAST(WeekTimeReported AS DATE) WeekTimeReported
,@rc:= CASE WHEN @cn=ClientName THEN @rc+1 ELSE 1 END AS rc
,desired_rank
,Hours
FROM sampledata , (select @rc:=0, @cn='') as rc
最佳答案
您需要考虑各个列的所有数据变化。
这是查询在 MySQL 8.0 中的样子
select
*
, dense_rank() over(partition by `ClientName` order by `WeekTimeReported`,`ProjectName`) rnk
from sampledata
ClientName | ProjectName | GroupName | WeekTimeReported | rank | desired_rank | Hours | rnk :--------- | :---------- | :-------- | :--------------- | ---: | -----------: | ----: | --: X | ProjX | A | 2013-12-30 | 1 | 1 | 2 | 1 X | ProjX | B | 2013-12-30 | 2 | 1 | 10 | 1 X | ProjX | C | 2014-01-06 | 3 | 2 | 4 | 2 X | ProjX | D | 2014-01-06 | 4 | 2 | 2 | 2 Y | ProjY | A | 2014-01-13 | 5 | 1 | 3 | 1 Y | ProjY | B | 2014-01-13 | 6 | 1 | 1 | 1 Y | ProjY | C | 2014-01-20 | 7 | 2 | 6 | 2 Y | ProjY | D | 2014-01-20 | 8 | 2 | 1 | 2 Z | ProjZ | A | 2014-01-27 | 9 | 1 | 4 | 1 Z | ProjZ | B | 2014-01-27 | 10 | 1 | 1 | 1 Z | ProjZ | C | 2014-02-03 | 11 | 2 | 17 | 2 Z | ProjZ | D | 2014-02-03 | 12 | 2 | 16 | 2
db<> fiddle here
这是对旧版 MySQL 的部分回答，希望可以帮助您实现目标:
查询 1:
select
rc - rcwk
, d.*
from (
SELECT
@rcwk:= CASE WHEN @cnwk=concat(ClientName,WeekTimeReported) THEN @rcwk+1 ELSE 1 END AS rcwk
, @rc:= CASE WHEN @cn=ClientName THEN @rc+1 ELSE 1 END AS rc
, desired_rank
, ClientName
, ProjectName
, GroupName
, CAST(WeekTimeReported AS DATE) WeekTimeReported
, Hours
, @cn:=ClientName
, @cnwk:=concat(ClientName,WeekTimeReported) abc
FROM sampledata
cross join (select @rc:=0,@rcwk:=0, @cn='',@cnwk='' ) as rc
order by ClientName, ProjectName, WeekTimeReported
) d
Results :
| rc - rcwk | rcwk | rc | desired_rank | ClientName | ProjectName | GroupName | WeekTimeReported | Hours | @cn:=ClientName | abc |
|-----------|------|----|--------------|------------|-------------|-----------|------------------|-------|-----------------|-------------|
| 0 | 1 | 1 | 1 | X | ProjX | A | 2013-12-30 | 2 | X | X2013-12-30 |
| 0 | 2 | 2 | 1 | X | ProjX | B | 2013-12-30 | 10 | X | X2013-12-30 |
| 2 | 1 | 3 | 2 | X | ProjX | C | 2014-01-06 | 4 | X | X2014-01-06 |
| 2 | 2 | 4 | 2 | X | ProjX | D | 2014-01-06 | 2 | X | X2014-01-06 |
| 0 | 1 | 1 | 1 | Y | ProjY | A | 2014-01-13 | 3 | Y | Y2014-01-13 |
| 0 | 2 | 2 | 1 | Y | ProjY | B | 2014-01-13 | 1 | Y | Y2014-01-13 |
| 2 | 1 | 3 | 2 | Y | ProjY | D | 2014-01-20 | 1 | Y | Y2014-01-20 |
| 2 | 2 | 4 | 2 | Y | ProjY | C | 2014-01-20 | 6 | Y | Y2014-01-20 |
| 0 | 1 | 1 | 1 | Z | ProjZ | A | 2014-01-27 | 4 | Z | Z2014-01-27 |
| 0 | 2 | 2 | 1 | Z | ProjZ | B | 2014-01-27 | 1 | Z | Z2014-01-27 |
| 2 | 1 | 3 | 2 | Z | ProjZ | C | 2014-02-03 | 17 | Z | Z2014-02-03 |
| 2 | 2 | 4 | 2 | Z | ProjZ | D | 2014-02-03 | 16 | Z | Z2014-02-03 |
关于MYSQL 基于多列的Rank，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/34319552/