Invoice
| id | invoice_date|
123435 2016/02/09
123436 2016/02/09
123437 2016/02/09
Payments
|invoice_id| pmt_type| amount |
123435 1 1000
123435 2 2500
123436 2 5000
...
Payments_legend
|type| description|
1 cash
2 check
3 credit
我对这个感到头疼。我需要提取日常交易并认为这很简单。我遇到的问题是许多嵌套连接,除非有更简单的方法来做到这一点。从表面上看,它确实很简单。
下面给出了我需要的所有发票...
SELECT id AS Invoice FROM invoice WHERE DATE(invoice_date) = DATE(NOW())
但这就是我感到困惑的地方。我需要按发票分组的每个 payments.amount 列的总和,并为每个 payments.pmt_type 分成列。哎呀。
我需要的报告如下...
id sum(pmt_type=1) sum(pmt_type=2) sum(pmt_type=3)
看起来像...
Invoice Cash Check Credit
123435 1000 2500 0
123436 0 5000 0
123437 0 0 7500
如有任何帮助,我们将不胜感激。
感谢 NECULON 的帮助
SELECT invoice.id,
sum(if(payments.pmt_type = 1, payments.amount, 0)) AS Cash,
sum(if(payments.pmt_type = 2, payments.amount, 0)) AS Chek,
sum(if(payments.pmt_type = 3, payments.amount, 0)) AS Credit,
sum(if(payments.pmt_type = 9, payments.amount, 0)) AS Warranty,
sum(if(payments.pmt_type = 10, payments.amount, 0)) AS Paypal,
sum(if(payments.pmt_type = 7, payments.amount, 0)) AS Refund,
(sum(if(payments.pmt_type = 1, payments.amount, 0))+sum(if(payments.pmt_type = 2, payments.amount, 0))+sum(if(payments.pmt_type = 3, payments.amount, 0))+sum(if(payments.pmt_type = 9, payments.amount, 0))+sum(if(payments.pmt_type = 10, payments.amount, 0))-sum(if(payments.pmt_type = 7, payments.amount, 0))) AS Total
FROM invoice
JOIN payments ON invoice.id = payments.invoice_id
WHERE DATE(invoice_date) = DATE(now())
GROUP BY invoice.id WITH ROLLUP
这给了我我所需要的。再次感谢!
最佳答案
尽量使用“IF”或“CASE”。像这样:
select
invoice.id,
sum(if(payments.pmt_type = 1, payments.amount, 0)) cash,
sum(if(payments.pmt_type = 2, payments.amount, 0)) check,
sum(if(payments.pmt_type = 3, payments.amount, 0)) credit
from invoice
join payment on invoice.id = payments.invoice_id
where date(invoice_date) = date(now())
group by invoice.id
参见此处:http://dev.mysql.com/doc/refman/5.7/en/control-flow-functions.html#function_if
关于MySql 3 表,嵌套连接,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/35298611/