我正在运行一个 sql 查询并返回结果，我怎样才能设置一个等于查询结果的选择列表？这是我的语法，但我不确定如何将返回的结果关联到选择？
默认情况下，我希望选择具有空值。
<?php
$servername = "localhost";
$username = "username";
$password = "password";
$dbname = "dbTest";
$conn = new mysqli($servername, $username, $password, $dbname);
if ($conn->connect_error) { die("Connection failed: " . $conn->connect_error); }
$sql = "Select CONCAT_WS(' ', name1, name2) As 'employeeName' from employees";
$result = $conn->query($sql);
if ($result->num_rows > 0)
{
while($row = $result->fetch_assoc()) { echo $row['employeename'] ."<br>"; }
}
$conn->close();
?>
<html>
<body>
<h4>Opening Header</h4>
<form>
<select>
<option>Set this to $result</option>
</select>
</form>
</body>
</html>
编辑 --- 所以 $result 将包含像
这样的值Bob Jones
Mitch Sandberg
Jose Mintz
而且我希望所有 3 个都是不同的值，以便在选择中进行选择。
最佳答案
只需将 php 脚本放在 select 标记之后，并将 option 标记放在循环内的 echo 上。
<html>
<body>
<h4>Opening Header</h4>
<form>
<select>
<option value="null" selected="selected">Default</option>
<?php
$servername = "localhost";
$username = "username";
$password = "password";
$dbname = "dbTest";
$conn = new mysqli($servername, $username, $password, $dbname);
if ($conn->connect_error) { die("Connection failed: " . $conn->connect_error); }
$sql = "Select CONCAT_WS(' ', name1, name2) As 'employeeName' from employees";
$result = $conn->query($sql);
if ($result->num_rows > 0)
{
while($row = $result->fetch_assoc()) { echo "<option value=".$row['employeename'].">".$row['employeename']."</option><br>"; }
}
$conn->close();
?>
</select>
</form>
</body>
关于php - 将选择选项设置为等于 MySQL 查询，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/36252281/