php - MySQL PHP - 用于不同值输出的变量

Question

我正在使用下面的查询来计算“Period”列中具有不同值的记录数量。 Period 列包含“Breakfast”、“Lunch”或“Dinner”，公式的输出按月列分组，然后每个不同的值一行:

TTL。意见反馈:早餐:XXX

TTL。反馈:午餐:XXX

TTL。意见反馈:晚餐:XXX

现在，我需要的是每个总数的变量(请参阅为早餐、午餐和晚餐返回的 $mydata['total']。当前变量仅返回每个不同值的总数，并且不让我专门针对个人期间得分。

    <?
    $whereParts = array();
    if ($property) {
        $whereParts[] = "Holidex = '$property' ";
    } 

    $whereParts = array();
    if ($outlet) {
        $whereParts[] = "Outlet = '$outlet' ";
    } 

    if ($pickyear) {
        $whereParts[] = "YEAR(Date) = '$pickyear' ";
    } 

    $sql = ("select distinct period from FB_Feedback_Card_Data");

    //BUILD THE FINAL QUERY
    if (count($whereParts) > 0) {
        $sql .= " WHERE " . implode('AND ', $whereParts);
    } 
    //count($whereParts) > 0

    $result = $mysqli->query($sql) or die('<p>Query to get case Period data from FB_Feedback_Card_Data table failed:' . mysql_error() . '</p>');

    while ($row = mysqli_fetch_row($result)) 
    {
        $period = $row[0];
        //echo "$status <br>";
        $mydata = stats("period", "$period", "$property", "$outlet", "$pickyear",$mysqli);

    ?>

<tr>
    <td class="result_desc"><?echo "Ttl. Feedback : $period";?></td>
    <td class="result"><? echo $mydata['a']; ?></td>
    <td class="result"><? echo $mydata['b']; ?></td>
    <td class="result"><? echo $mydata['c']; ?></td>
    <td class="result"><? echo $mydata['d']; ?></td>
    <td class="result"><? echo $mydata['e']; ?></td>
    <td class="result"><? echo $mydata['f']; ?></td>
    <td class="result"><? echo $mydata['g']; ?></td>
    <td class="result"><? echo $mydata['h']; ?></td>
    <td class="result"><? echo $mydata['i']; ?></td>
    <td class="result"><? echo $mydata['j']; ?></td>
    <td class="result"><? echo $mydata['k']; ?></td>
    <td class="result"><? echo $mydata['l']; ?></td>
    <td class="result_ytd"><strong><? echo $mydata['total']; ?></strong></td>
</tr>

<?
// end total status stats
}
?>

Answer 1

你不需要为此使用DISTINCT，你需要GROUP BY，它将所有具有相同值的条目放在同一条记录上，然后你只需要数一数:

SELECT period, count(period) as period_count FROM FB_Feedback_Card_Data WHERE ... GROUP BY period

复制代码