php - 如何从 mysql 获取客户 ID，然后将其存储在 session 变量中以使用另一个文件中的 session 变量来检索信息

Question

我是 PHP 新手。 我制作了一个登录页面和一个注册页面，我想在成功登录或注册后将客户 ID 存储在我的 session 变量中，以便稍后在我的购物车文件中使用 session 变量来检索该客户的购物车详细信息。客户 ID 在表中自动递增，因此我不会从客户那里获取客户 ID 的输入。 这是代码

登录.php:

    <?php
session_start();
$db=mysqli_connect("localhost","root","Naruto97","musicgallery");

if (isset($_POST['login_btn'])){
    $email = mysqli_real_escape_string($db,$_POST['email']);
    $password = mysqli_real_escape_string($db,$_POST['password']);
    $password=md5($password);
    $sql="SELECT * FROM LoginCredentials WHERE email='$email' AND password='$password'";
    $result = mysqli_query($db,$sql);
    if(mysqli_num_rows($result)==1){
        $_SESSION['message']="You are now logged in";
        $_SESSION['email']=$email;
        //Want to store the customer in session variable here after successful login
        header("location:home.php");
    }
    else{
        $_SESSION['message']= "Email/Password combination Incorrect";
    }
}

   ?>

注册.php:

     <?php
session_start();
$db=mysqli_connect("localhost","root","Naruto97","musicgallery");

if (isset($_POST['register_btn'])){

    $username = mysqli_real_escape_string($db,$_POST['username']);
    $email = mysqli_real_escape_string($db,$_POST['email']);
    $password = mysqli_real_escape_string($db,$_POST['password']);
    $password2 = mysqli_real_escape_string($db,$_POST['password2']);

    if($password==$password2){
        $password=md5($password);
        $sql = "INSERT INTO LoginCredentials(Username,email,password) VALUES('$username','$email','$password')";
        mysqli_query($db, $sql);
        $_SESSION['message']="You are now logged in";
        $_SESSION['email']=$email;
        //Want to store the customer_id here in the session variable after successful registration
        header("location:home.php");
    }else{
        $_SESSION['message']="The passwords do not match";

    }
}
   ?>

购物车.php:

     <?php
       session_start();
       $db=mysqli_connect("localhost","root","Naruto97","musicgallery");
       if(isset($_POST["add_to_cart"])){
         if(isset($_SESSION['email'])){
           $album_name = mysqli_real_escape_string($db,$_POST['hidden_name']);
           $price = mysqli_real_escape_string($db,$_POST['hidden_price']);
           $quantity = mysqli_real_escape_string($db,$_POST['quantity']);
           //$customer_id= $_SESSION['customer_id'];
           $sql = "INSERT INTO cart(album_name,price,quantity,customer_id) VALUES('$album_name','$price','$quantity','$customer_id')";
          mysqli_query($db, $sql);
          echo "<script>alert('Added to cart')</script>";
          echo "<script>window.location('kpop.php')</script>";
          } 
          else
          {
             echo "<script>alert('Please Login')</script>";
             echo "<script>window.location('kpop.php')</script>";
          }
      }
     ?>

Answer 1

要获取 mysqli 中的最后一个 insertid，请使用:-

  $sql = "INSERT INTO cart(album_name,price,quantity,customer_id) VALUES('$album_name','$price','$quantity','$customer_id')";
      mysqli_query($db, $sql);


$_SESSION['customerId']=mysqli_insert_id($db);//gets the last inserted customerid from db

如需进一步引用，您可以查看此 link .