假设我有如下表格:
日程安排
+-------+------------+--------+----------------+-------+---------+
| index | date | empid | dept | sfrom | slength |
+-------+------------+--------+----------------+-------+---------+
| 0 | 09-24-2018 | 943023 | RADIOLOGY | 03PM | 8 |
| 1 | 09-24-2018 | 891046 | SURGERY | 07AM | 8 |
| 2 | 09-24-2018 | 878397 | RADIOLOGY | 11PM | 8 |
| 3 | 09-24-2018 | 886190 | CARDIOLOGY | 03PM | 8 |
| 4 | 09-24-2018 | 878397 | RADIOLOGY | 11PM | 8 |
| 5 | 09-24-2018 | 891330 | SURGERY | 03PM | 8 |
| 6 | 09-24-2018 | 995561 | SURGERY | 11PM | 8 |
| 7 | 09-24-2018 | 967577 | MATERNITY | 03PM | 8 |
| 8 | 09-24-2018 | 913891 | PEDIATRICS | 03PM | 8 |
| 9 | 09-24-2018 | 939148 | EMERGENCY | 07AM | 8 |
| 10 | 09-24-2018 | 995636 | RADIOLOGY | 11PM | 8 |
| 11 | 09-24-2018 | 995561 | EMERGENCY | 11PM | 8 |
| 12 | 09-24-2018 | 967577 | SURGERY | 07AM | 8 |
| 13 | 09-24-2018 | 883069 | INTENSIVE CARE | 07AM | 8 |
| 14 | 09-24-2018 | 951876 | ONCOLOGY | 03PM | 8 |
| 15 | 09-24-2018 | 884866 | CARDIOLOGY | 07AM | 8 |
| 16 | 09-24-2018 | 864425 | ONCOLOGY | 03PM | 8 |
员工表
+-------+--------+------------+-----------+---------+----------------+----------------+------+
| index | empid | lastName | firstName | emptype | cellphone | homephone | ftpt |
+-------+--------+------------+-----------+---------+----------------+----------------+------+
| 0 | 919675 | Cermak | Vern | LPN | (138)7198-0862 | (655)2249-9926 | FT |
| 1 | 906704 | Paille | Lorilee | NULL | (858)1100-2722 | (377)1506-1986 | PT |
| 2 | 900486 | Ober | Shalanda | NULL | (210)1508-8132 | (820)1612-0197 | FT |
| 3 | 883367 | Clyburn | Jeffry | LPN | (420)7798-7220 | (476)7661-3070 | FT |
| 4 | 953807 | Quarles | Timmy | LPN | (513)2756-9892
如果我必须计算每个部门每个员工类型和每个类次的总成本,我应该如何在 sql 中执行此操作?
Given that if a shift includes midnight I multiply my wage by 25% ?
我有一个示例输出如下,但不知道如何执行此操作?:
+------------+---------------+----------------+---------+
| DEPARTMENT | EMPLOYEE_TYPE | SHIFT | COST |
+------------+---------------+----------------+---------+
| Anesthesia | LPN | 7 AM –3 | $24,567 |
| Anesthesia | LPN | 3 PM –11PM | $18,546 |
| Anesthesia | LPN | 11 PM –7AM | $22,874 |
| Anesthesia | NA | 7 AM –3 PM | $9,764 |
| Anesthesia | NA | 3 PM –11 PM | $10,287 |
| Anesthesia | NA | 11 PM –7 AM | $6, 875 |
| Anesthesia | RN | 7 AM –3 PM | $33,123 |
+------------+---------------+----------------+---------+
到目前为止,这是我的 sql 语句: 但是我应该如何让它工作呢? 编辑 1:
Select
t1.dept,
t2.emptype,
t1.sfrom,
t1.slength,
SUM(t1.slength) as hours
CASE WHEN CAST(STR_TO_DATE(sfrom,'%h%p') +
STR_TO_DATE(slength,'%H')) > STR_TO_DATE(23,'%H')
then (slength*10*1.25) else (slength*10) end as cost
from
schedule_2 as t1
Join (select
empid,
emptype
from
employees_2) as t2 ON t1.empid=t2.empid
GROUP BY
dept,
emptype,
slength;
编辑2:
Select
t1.dept,
t2.emptype,
t1.sfrom,
t1.slength,
SUM(t1.slength) as hours
CASE WHEN HOUR(STR_TO_DATE(sfrom,'%h%p') +
STR_TO_DATE(slength,'%H')) > 23
then (slength*10*1.25) else (slength*10)
from
schedule_2 as t1
Join (select
empid,
emptype
from`
employees_2) as t2 ON t1.empid=t2.empid
GROUP BY
dept,
emptype,
slength;
我收到以下错误,但似乎无法弄清楚原因?
You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near 'CASE WHEN HOUR(STR_TO_DATE(sfrom,'%h%p') + STR_TO_DATE(slength,'%H')) > 23 then ' at line 2
最佳答案
您可以在您的 sql 语句中为成本字段使用 case 子句。例如:
case when <<your clause for night shift>> then (slength*10)+(0.25*10*slength)
else (slength*10) end as cost
假设是每小时 10 美元。您可以根据业务规则设置夜类条件。
关于mysql - 带条件乘法的sql语句应该怎么写?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/53094862/