我已经看到了这段代码,但是从这里我必须手动插入所有列并按每一列进行检查
CREATE TRIGGER table_a_update BEFORE UPDATE ON table_a
FOR EACH ROW
BEGIN
IF (NEW.column1 <=> OLD.column1)
THEN
INSERT INTO table_updates(table, object_id, user_id, column, old_value, new_value)
VALUES ("table_a",NEW.id, NEW.user_id, "column1", OLD.column1, new.column1)
END IF;
IF (NEW.column2 <=> OLD.column2)
THEN
INSERT INTO table_updates(table, object_id, user_id, column, old_value, new_value)
VALUES ("table_a",NEW.id, NEW.user_id, "column2", OLD.column2, new.column2)
END IF;
(other columns... ifs)
END;
我想知道如何从 NEW 中获取与 OLD 列有差异的所有列,然后将其插入,例如使用 php 来插入我不知道的内容:
BEGIN
for(columns(NEW) as $column){
IF (NEW.$column <=> OLD.$column)
THEN
INSERT INTO table_updates(table, object_id, user_id,column, old_value, new_value)
VALUES ("table_a", NEW.id, NEW.user_id, $column, $OLD[$column], $NEW[$column])
END IF;
}
END;
最佳答案
IIUC:
DELIMITER $$
CREATE TRIGGER before_update_table_a
BEFORE UPDATE ON table_a
FOR EACH ROW BEGIN
IF (NEW.col1 <> OLD.col1) THEN
INSERT INTO table_updates (col1, col2, ...
VALUES (OLD.col1, NEW.col2 ...
END IF;
IF (NEW.col2 <> OLD.col2) THEN
INSERT INTO table_updates (col1, col2, ...
VALUES (NEW.col1, OLD.col2 ...
END IF;
...
END $$
DELIMITER ;
我相信您需要在此触发器中使用DELIMITER
关键字,如果您想了解更多相关信息,请查看this问题。
关于MYSQL更新触发器检查所有列的更改并将值插入到其他表,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/55329692/