mysql - 获取 mySQL 存储过程导致另一个存储过程

标签 mysql sql stored-procedures

我需要一个存储过程的示例,它使用另外两个存储过程(或什至只是一个)的结果,其中结果用作组合存储过程中的表。我可能会从那里拿走它。

网络(多个站点)上的示例和 php.net 上的详细信息过于简单。

基本问题可以看这里:

SELECT ttd.person_id, weight, min(test_date)
FROM (
  CALL get_team_member_body_stats(1) AS tbs,   
  CALL get_team_member_first_last_test_date(1) AS ttd
  WHERE tbs.person_id = ttd.person_id
  AND (tbs.test_date = ttd.first_test OR tbs.test_date = ttd.last_test)
  GROUP BY ttd.person_id;
END

感谢您的帮助。在昨天和今天的在线搜索和试验中,我已经为此苦苦思索了几个小时。

详细信息:

表1

存储过程 get_team_member_body_stats(IN team_id INT) 处理 5 个表(person、team、person_team、body_stats、person_body_stats)并产生:

person_id | body_stats_id | weight | test_date |   
  2         2               200      2011-01-01  
  4         3               250      2011-01-01  
  1         5               145      2011-03-01 
  2         6               210.4    2011-03-01 
  5         7               290      2011-03-01 
  1         8               140      2011-04-01 
  1         9               135      2011-05-01 
  4         11              245      2011-05-01 

表2

存储过程 get_team_member_first_last_test_date(IN team_id INT) 处理相同的表并生成:

person_id | first_test | last_test

1           2011-03-01   2011-05-01
2           2011-01-01   2011-03-01
4           2011-01-01   2011-05-01
5           2011-03-01   2011-03-01

目标是加入这些并产生:

表3

person_id | first_weight | last_weight

1           145            135
2           200            210.4 
4           250            245
5           290            290

谢谢

最佳答案

看来(根据这个社区,因为我找不到任何使用其他存储过程的结果集作为新选择表中的表的存储过程的示例)mysql 要么不支持这个,要么很难实现做我想做的事。

因此,我没有调用存储过程,而是将查询复制到这个最终过程中。


    DELIMITER $$

    CREATE DEFINER=`root`@`localhost` PROCEDURE `get_team_stats_change`(
        IN team_id INT
    )
    BEGIN
    SELECT SUM(start_weight) AS start_weight, 
        SUM(start_body_fat) AS start_body_fat, 
        SUM(current_weight) AS current_weight,
        SUM(current_body_fat) AS current_body_fat,
        SUM(weight_change) AS weight_change, 
        SUM(body_fat_change) AS body_fat_change FROM (
    SELECT ls.person_id, 
        fs.weight AS start_weight, fs.body_fat AS start_body_fat, 
        ls.weight AS current_weight, ls.body_fat AS current_body_fat,
        fs.weight - ls.weight AS weight_change, fs.body_fat - ls.body_fat AS body_fat_change
    FROM
    (SELECT ttd.person_id, bs.weight, bs.body_fat, bs.test_date
    FROM body_stats AS bs
    JOIN
        ((SELECT pbs.person_id,  min(bs.test_date)  AS first_test, max(bs.test_date) AS last_test   
        FROM body_stats AS bs,
            person_body_stats AS pbs,
            team_member AS tm,
            team AS t
        WHERE t.team_id = team_id
        AND tm.team_id = t.team_id
        AND tm.person_id = pbs.person_id
        AND pbs.body_stats_id = bs.body_stats_id
        AND tm.start_date  bs.test_date
        AND bs.test_date >= t.starting_date
        GROUP BY person_id) AS ttd,
        person_body_stats AS pbs)
    ON bs.test_date = ttd.first_test 
        AND pbs.person_id = ttd.person_id 
        AND pbs.body_stats_id = bs.body_stats_id) AS fs,

    (SELECT ttd.person_id, bs.weight, bs.body_fat, bs.test_date
    FROM body_stats AS bs
    JOIN
        ((SELECT pbs.person_id,  min(bs.test_date)  AS first_test, max(bs.test_date) AS last_test   
        FROM body_stats AS bs,
            person_body_stats AS pbs,
            team_member AS tm,
            team AS t
        WHERE t.team_id = team_id
        AND tm.team_id = t.team_id
        AND tm.person_id = pbs.person_id
        AND pbs.body_stats_id = bs.body_stats_id
        AND tm.start_date  bs.test_date
        AND bs.test_date >= t.starting_date
        GROUP BY person_id) AS ttd,
        person_body_stats AS pbs)
    ON bs.test_date = ttd.last_test 
        AND pbs.person_id = ttd.person_id 
        AND pbs.body_stats_id = bs.body_stats_id) AS ls
        WHERE ls.person_id = fs.person_id
       ) AS delta;
    END

关于mysql - 获取 mySQL 存储过程导致另一个存储过程,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/8662987/

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