我在嵌套 while 循环的第一个结果之后出现了一个表格。
我想做的是通过从“用户”表中选择来将用户名显示为列表,然后将该列表与“当前项目”表中的项目工程师进行比较。
这样就有一个项目工程师列表,他们的名字下面有分配给他们的项目。
不幸的是,我在第一个嵌套的 while 循环运行后吐出一个空表,我不确定如何摆脱它。
我怀疑它与 $proj_engineer = ""; 的初始变量有关
有谁知道这个空表是从哪里来的以及如何摆脱它?
代码如下:
<?php
$query = mysql_query("SELECT * FROM `users` ORDER BY `username` ASC") or die(mysql_error());
while ($row = mysql_fetch_assoc($query)) {
$user_id = $row['user_id'];
$username = $row['username'];
$proj_engineer = "";
$query1 = mysql_query("SELECT * FROM `current_projects` WHERE `proj_engineer`='$username' ORDER BY `proj_engineer` ASC") or die(mysql_error());
while ($row1 = mysql_fetch_assoc($query1)) {
$proj_id = $row1['proj_id'];
$proj_engineer = $row1['proj_engineer'];
}
echo "<table border=1><tr><td colspan=12><p class='bold18'>" . $proj_engineer . "</p></td></tr>";
$query3 = mysql_query("SELECT * FROM `current_projects` WHERE `proj_engineer`='$username' ORDER BY `proj_id` DESC") or die(mysql_error());
while ($row3 = mysql_fetch_assoc($query3)) {
$proj_id = $row3['proj_id'];
$proj_number = $row3['proj_number'];
$proj_name = $row3['proj_name'];
$proj_sort = $row3['proj_sort'];
$proj_start = $row3['proj_start'];
$proj_finish = $row3['proj_finish'];
$proj_overstat = $row3['proj_overstat'];
$proj_dwgstat = $row3['proj_dwgstat'];
$proj_soostat = $row3['proj_soostat'];
$proj_substat = $row3['proj_substat'];
$proj_engineer = $row3['proj_engineer'];
$proj_drafter = $row3['proj_drafter'];
$proj_rating = $row3['proj_rating'];
$proj_pending = $row3['proj_pending'];
$proj_notes = $row3['proj_notes'];
$start_time = date("m/d/y", $proj_start);
$finish_time = date("m/d/y", $proj_finish);
echo "
<tr>
<td width=40>$proj_number</td>
<td width=100>$proj_engineer</td>
<td width=100><a href='./project-page.php?proj_id=$proj_id'>$proj_name</a></td>
<td width=40>$start_time</td>
<td width=40>$finish_time</td>
<td width=110>
<div style='position:relative; background:url(images/bar01.gif); width:$proj_overstat; height:20;'>
<div style='position:absolute; bottom:0; left:0; width:$proj_overstat; font-weight:bold; color:#000000; vertical-align:middle; height:20; text-align:center;'>$proj_overstat%</div>
</div>
</td>
<td width=110>
<div style='position:relative; background:url(images/bar02.gif); width:$proj_dwgstat; height:20;'>
<div style='position:absolute; bottom:0; left:0; width:$proj_dwgstat; font-weight:bold; color:#000000; vertical-align:middle; height:20; text-align:center;'>$proj_dwgstat%</div>
</div>
</td>
<td width=110>
<div style='position:relative; background:url(images/bar03.gif); width:$proj_soostat; height:20;'>
<div style='position:absolute; bottom:0; left:0; width:$proj_soostat; font-weight:bold; color:#000000; vertical-align:middle; height:20; text-align:center;'>$proj_soostat%</div>
</div>
</td>
<td width=110>
<div style='position:relative; background:url(images/bar04.gif); width:$proj_substat; height:20;'>
<div style='position:absolute; bottom:0; left:0; width:$proj_substat; font-weight:bold; color:#000000; vertical-align:middle; height:20; text-align:center;'>$proj_substat%</div>
</div>
</td>
<td width=40 align='center'><a href='project-notes.php?proj_id=$proj_id'><img src='images/note.png' border=0></a></td>
<td width=40 align='center'><a href='./project-edit.php?proj_id=$proj_id'>EDIT</a></td>
<td width=40 align='center'><a href='./project-delete.php?proj_id=$proj_id'>DELETE</a></td>
</tr>
";
}
echo "</table><br>";
}
?>
最佳答案
这可能是因为,您的查询:-
$query1 = mysql_query("SELECT * FROM `current_projects` WHERE
`proj_engineer`='$username' ORDER BY `proj_engineer` ASC")
or die(mysql_error());
为您获取了 $proj_engineer
的空值。您可以在打印表格之前检查您的变量是否包含一个值。在打印 table
之前尝试打印 $proj_engineer
。
您可以将您的代码包含在 if
结构中回显
表格,只有当您的值不为空时才会打印表格。
关于PHP - 空表出现在嵌套 while 循环的第一个结果之后,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/12986560/