php - 在动态单选按钮循环中获取提交的值和名称时遇到问题

Question

我从 mysql 中选择了数据并将它们插入到循环的单选按钮表单中，如图所示:

if($num_rows) {

    echo '<form name="fixtureform" method="POST" action="index.php">';

    while ($row = mysql_fetch_assoc($result)) {

    echo $row["home_team"] . " vs " . $row["away_team"]. '<br />' . " Home" . '<input type="radio" name="win'.$row["home_id"].'" value="'.$row["home_id"].'"/>' ." Draw" . '<input type="radio" name="'.$row["home_id"].$row["away_id"].'" value="draw"/>' ." Away" . '<input type="radio" name="win'.$row["away_id"].'" value="' . $row["away_id"] . '"/>' .'<br />';

}
    echo '<input type="Submit" Name="Submitacc" Value="Submit your teams">';
    echo '</form>';

} else { 
        echo "There are no fixtures today ";
        }

然后我有一个用于提交值的 if 语句:

if($_POST['Submitacc']=='Submit your teams') {


    }

如果单选按钮的选定名称是 win.$row[home_id] - 将值插入 mysql 表，我会怎么说。我正在努力解决无法在循环之外获取 $row[home_id] 的事实？

提前致谢

Answer 1

尝试如下

$i=0;
while ($row = mysql_fetch_assoc($result)) {
    echo $row["home_team"] . " vs " . $row["away_team"]. '<br />' . " Home" . '<input type="radio" name="result['.$i.']" value="h_'.$row["home_id"].'"/>' ." Draw" . '<input type="radio" name="result['.$i.']" value="draw"/>' ." Away" . '<input type="radio" name="result['.$i.']" value="a_' . $row["away_id"] . '"/>' .'<br />';
  $i++;
}

在你的 PHP 中

foreach($_POST['result'] as $value){
   if($value == 'draw') {
     //do stuff
   }
   else {
     $apart = explode('_',$value);
     if($apart[0]=='h'){
        //home team win
        echo $apart[1];
     }
     else {
        //away team win
        echo $apart[1];          
     }
   } 
}