我正在尝试根据以下条件从我的表中获取一些行:
SELECT * FROM MyTable WHERE Date BETWEEN
CASE dayofweek(curdate())
when 1 then curdate() AND adddate(curdate(), interval 6 day)
when 2 then subdate(curdate(), interval 1 day) AND adddate(curdate(), interval 5 day)
when 3 then subdate(curdate(), interval 2 day) AND adddate(curdate(), interval 4 day)
when 4 then subdate(curdate(), interval 3 day) AND adddate(curdate(), interval 3 day)
when 5 then subdate(curdate(), interval 4 day) AND adddate(curdate(), interval 2 day)
when 6 then subdate(curdate(), interval 5 day) AND adddate(curdate(), interval 1 day)
when 7 then subdate(curdate(), interval 6 day) AND curdate()
END
但由于某些原因它不起作用。它给了我一个语法错误。我应该如何完成这样的事情?
最佳答案
试试这个,
SELECT *
FROM MyTable
WHERE 1 =
CASE dayofweek(curdate())
when 1 then Date BETWEEN curdate() AND adddate(curdate(), interval 6 day)
when 2 then Date BETWEEN subdate(curdate(), interval 1 day) AND adddate(curdate(), interval 5 day)
when 3 then Date BETWEEN subdate(curdate(), interval 2 day) AND adddate(curdate(), interval 4 day)
when 4 then Date BETWEEN subdate(curdate(), interval 3 day) AND adddate(curdate(), interval 3 day)
when 5 then Date BETWEEN subdate(curdate(), interval 4 day) AND adddate(curdate(), interval 2 day)
when 6 then Date BETWEEN subdate(curdate(), interval 5 day) AND adddate(curdate(), interval 1 day)
when 7 then Date BETWEEN subdate(curdate(), interval 6 day) AND curdate()
END
在这种情况下,CASE()
语句只会返回两个可能的值:1
和 0
。
关于mysql - 在 WHERE 子句和 BETWEEN 运算符中使用 CASE 表达式,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/16129181/