我的广告门户有 4 个表格。 首先主表名称是ads
+-------------+
| Field +
+-------------+
| id +
| ads_title +
+-------------+
广告表的示例数据；
+----+-----------------+
| id | ads_title |
+----+-----------------+
| 20 | 2006 CITROEN C4 |
| 27 | EMEKLI OGRETMEN |
| 28 | Harika 10 n |
| 34 | HATASIZ BOYASIZ |
| 49 | BAYANDAN 2009 |
+----+-----------------+
用于存储在表中的广告规范。表名是ads_spc
+---------+
| Field |
+---------+
| id |
| key_name|
+---------+
ads_spc 表的数据示例；
+----+-------------+
| id | key_name |
+----+-------------+
| 1 | Date |
| 2 | Km |
| 3 | Colr |
| 4 | Engine |
| 5 | Pw. Engine |
| 6 | Oil |
| 7 | Speed |
| 8 | Boody Type |
| 9 | Traction |
| 10 | Warranty |
+----+-------------+
最后按 ads_id 存储的 ads_spc 规范值。表名是 ads_values
+------------+
| Field |
+------------+
| id |
| ads_id |
| spc_id |
| value |
+------------+
比如这张表数据
+----+--------+--------+-------+
| id | ads_id | spc_id | value |
+----+--------+--------+-------+
| 25 | 49 | 9 | 2119 |
| 26 | 49 | 10 | 2131 |
| 27 | 34 | 1 | 2010 |
| 28 | 34 | 2 | 8900 |
| 29 | 34 | 3 | 4 |
| 30 | 34 | 4 | 22 |
| 31 | 34 | 5 | 40 |
| 32 | 34 | 6 | 60 |
| 33 | 34 | 7 | 65 |
| 34 | 34 | 8 | 66 |
+----+--------+--------+-------+
我想使用这些表格在数据行中列出广告 (table:ads) 和规范 (table:ads_spc) 和广告值 (table:ads_values)。
联合到； ADS + ADS_SPC + ADS_VALUES(所有值均可搜索)
我正在使用这种情况:
SELECT SQL_CALC_FOUND_ROWS
*
FROM ads AS a
LEFT JOIN ads_spc AS aspc
LEFT JOIN ads_values AS aval ON aval.ads_id=a.id AND aval.spc_id=aspc.spc_id
如何合并到一行？ 对不起我的英语。
最佳答案
为什么 union 对于 union 你应该加入这些表是没有意义的
SELECT v.id, a.ads_title,s.key_name,v.value FROM `ads` a
INNER JOIN `ads_values` v ON (a.id =v.ads_id)
INNER JOIN `ads_spc` s ON(v.spc_id =s.id) WHERE s.key_name='Color'
关于php - 从多个表中获取数据，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/18113552/