php - 使用php将多个文件上传到服务器而不是将所有文件上传到服务器

Question

大家好，我遇到了一个问题，我有一个表格可以上传文件并插入到 mysql 中，mysql 插入部分正在工作，但他只将三个文件中的一个文件移动到服务器需要请一些帮助这是我的代码。 上传表格:

<form enctype="multipart/form-data" action="add-exposes.php" method="POST">  Expose Name: <input type="text" name="name"><br>  Expose Beschreibung: <textarea style="width: 810px; height: 200px" name="expose_desc" class="textarea"></textarea><br>  Expose Kategorie:<select name="expose_cat" size="3"> 
                        <?php 
                    mysql_connect("xxx.de.mysql", "xxxx", "xxx") or die(mysql_error()) ;  mysql_select_db("handwerker_verb") or die(mysql_error()) ;

                    $data = mysql_query("SELECT * FROM cats") or die(mysql_error());
                    while($info = mysql_fetch_array( $data )) {
                    echo '<option value="'.$info['id'].'">'.$info['cat'].'</option>';
                    } ?>


                         </select><!--<input type="text" name="expose_cat">--><br>Expose Preis:<input type="text" name="price"> <br> Bild: <input type="file" name="photo"><br> <input type="file" name="photo1"><br> <input type="file" name="photo2"><br>   <input type="submit" value="Add">  </form>

添加到服务器和mysql:

<?php   $target = "images/";  $target = $target . basename( $_FILES['photo']['name']);
$target1 = "images/";  $target1 = $target1 . basename( $_FILES['photo1']['name']);
$target2 = "images/";  $target2 = $target2 . basename( $_FILES['photo2']['name']);

        $name=$_POST['name'];  $expose_desc=$_POST['expose_desc'];  $expose_cat=$_POST['expose_cat'];  $pic=($_FILES['photo']['name']);  $price=$_POST['price']; $pic1=($_FILES['photo1']['name']); $pic2=($_FILES['photo2']['name']); 

        mysql_connect("xxxx.de.mysql", "xx", "xxx") or die(mysql_error()) ;  mysql_select_db("handwerker_verb") or die(mysql_error()) ;

          mysql_query("INSERT INTO `exposes` VALUES ('', '$name', '$pic', '$expose_desc', '$expose_cat', '$price', '$pic1', '$pic2' )") ; 

          if(move_uploaded_file($_FILES['photo']['tmp_name'], $target))  {   echo "The file ". basename( $_FILES['uploadedfile']['name']). " has been uploaded, and your information has been added to the directory";  } 
          elseif(move_uploaded_file($_FILES['photo1']['tmp_name'], $target1))  {   echo "The 2 file ". basename( $_FILES['uploadedfile']['name']). " has been uploaded, and your information has been added to the directory";  } 
          elseif(move_uploaded_file($_FILES['photo2']['tmp_name'], $target2))  {   echo "The 3 file ". basename( $_FILES['uploadedfile']['name']). " has been uploaded, and your information has been added to the directory";  }

           else {    echo "Sorry, there was a problem uploading your file.";  }  ?>                         

Answer 1

move_uploaded_file 成功返回 true，其余 elseif 永远不会到达。 尝试这样的事情:

$error = false;

if(move_uploaded_file($_FILES['photo']['tmp_name'], $target))  
{   
echo "The file ". basename( $_FILES['uploadedfile']['name']). " has been uploaded, and your information has been added to the directory";  
} else $error = true;

if(move_uploaded_file($_FILES['photo1']['tmp_name'], $target1))  
{   
echo "The 2 file ". basename( $_FILES['uploadedfile']['name']). " has been uploaded, and your information has been added to the directory";  
} else $error = true; 

if(move_uploaded_file($_FILES['photo2']['tmp_name'], $target2))  
{   
echo "The 3 file ". basename( $_FILES['uploadedfile']['name']). " has been uploaded, and your information has been added to the directory";  
} else $error = true;

if($error)
   echo "Sorry, there was a problem uploading your file.";